CHAPTER-1
alphabetical and
miscellaneous SERIES
This chapter is based on
series of numbers, letters or combination of letters, numbers and symbols.
Type of series-
(1) Letter series
(2) Number series
(3) Miscellaneous series.
Position of letters:
First of all, we should know the position of
all letters from A to Z.
With the help of some words we can get the position of total 26 letters.
Opposite of
letters:
AaZad
BoY
CoreX
DeW
EVening
FUel
GeT
High School
Indian Railway
Jack Queen
KeeP
LOve
MaN
Also we have tried to
incorporate those questions which do not find place in any other chapter. We
have endeavored to identify all types of these questions and place them in this
chapter.
Dear students following
examples will help you to recognize these
questions and understand the methods
for solving them.
TYPE- 1
EX.1. Arrange the following words in alphabetical
order and choose the word that comes exactly in the middle.
(a) Arrangement (b)
Arrest (c) Arrears
(d) Arrival (e)
Arrogant
SOLUTION
If we arrange all the five words in the form which are occupy in
dictionary, we get their order of positions as-
(1) Arrangement
(2) Arrears
(3) Arrest
(4) Arrival
(5) Arrogant
We find that the word Arrest comes in the middle. Hence, our answer is (2).
TYPE-2
EX.1. If it is possible to form a word with the
first, fourth, seventh and eleventh letters of the word “SUPERFLUOUS”,
write the first letter of that word. Otherwise, Z is your answer.
(1) S (2) L (3) O (4)
E (5) Z
SOLUTION
LESS is the word which is formed by using first,
fourth, seventh and eleventh letters of the word SUPERFLUOUS.
First letter of this word is L. Hence our answer is (2).
EX.2. How many meaningful English words can be formed with the
letters L, G, E, U using each letter only once in each word?
(1) None (2)
One (3) Two (4) Three
(5) More than three
SOLUTION
UGLY
Hence option (2) is correct.
TYPE-3
EX.1. How many pairs of letters are there in the word “SEQUENTIAL”
which have as many letters between them (from both sides) as they have in the
English alphabets?
(1) One (2) Two (3) Three (4) Four
(5) More than four
SOLUTION
From the word that S (E) Q, Q (UE) N, S (EQUE) N, E (NTI) A
are the pairs which have as many letters between them as in the
alphabetical order. Hence our answer is (4).
TYPE-4
EX.1. Four
of the following five are alike in a certain way and hence form a group. Which
is the one that does not belong to the group?
(1) Scientist
(2) Engineer
(3) Teacher
(4) Architect
(5) Doctor
SOLUTION
All the rest are exclusive
professions while a teacher may be there in any of these categories. Hence option
(3) is answer.
TYPE- 5
EX.1. If ‘Rain’ denotes ‘-‘
,’Queen’ denotes ‘X’ and ‘Apple’ denotes
‘+‘, then
42 Rain 7 Rain 8 Apple 6
Queen 4 = ?
(1) -62 (2) - 68 (3) 51 (4) 68
(5) None of these
SOLUTION
Using BODMAS rule
B------- Brackets
O------- Of
D------ Divide
M------ Multiply
A------ Addition
S------Subtraction
42 Rain 7 Rain 8 Apple 6
Queen 4
= 42 - 7 - 8 + 6 X 4
= 42 – 7 – 8 + 24
= 66 – 15 = 51
Hence option (3) is
correct.
TYPE- 6
EX.1. What
should come next in the following letter series based on English alphabet?
CEA IKG OQM
(?)
(1) STW (2) WUS (3) SWU (4) UWS
(5) None of these
SOLUTION
C (+6 = 9) I
E (+6 = 11) K
A (+6 = 7) G
O (+6 = 21) U
Q (+6 = 23) W
M (+6 = 19) S
Hence option (4) is correct.
EX.2. What should come next
in the following letter series?
PQRSTABCDEPQRSABCDPQRABCPQA
(1) R (2) T
(3) A (4) B
(5) None of these
SOLUTION
PQRST / ABCDE / PQRS / ABCD /
PQR / ABC / PQ / AB
Hence option (4) is correct.
TYPE- 7
EX.1. The positions
of how many digits in the number 59164823 will remain unchanged after the digits
are rearranged in descending order within the number?
(1) None (2)
One (3) Two (4) Three
(5) More than three
SOLUTION
Number- 59164823
On arranging in descending
order, we get – 98654321
Here, the place of 4 and 2
are unchanged in the number 98654321.
Hence option (3) is
true.
TYPE-8
LETTER SERIES: In
this series only letters are available which follow a certain pattern
throughout. Candidate has to recognize this pattern and to give the required
answer.
A B
C D E
F G H
I J K
L M N
O P Q
R S T
U V W
X Y Z
EX.1.How
many such vowels are there in the above arrangement each of which is
immediately preceded as well as followed by a consonant?
(1) One (2)
Two (3) Three (4) Four (5) None of these
SOLUTION
Consonant Vowel Consonant
D
E F
H
I J
N
O P
T U V
Hence option (4) is correct.
TYPE-9
NUMBER SERIES: In this series questions are based on numbers.
1 2 6 5 3 2 1 8 9 6
5 3 2 1 2 3 1
EX.1.
How
many 1’s are there in the above arrangement each of which is followed by 2?
(1)
One (2) Two (3) Three (4) Four (5) None of these
SOLUTION
1 2
6 5 3 2 1 8 9 6 5 3 2 1 2 3 1
Hence option (2) is correct.
TYPE-10
MISCELLANEOUS SERIES:
In this segment, given questions
are related to the position of letters, numbers and symbols.
Memorable Points:
Dear Students, you can
easily solve the problems based on this chapter with the help of these short tricks
–
(i) Starting point of the
series is left end and ending point of the series is right end.
(ii) To solve the question
easily you should break the series in
combination of five- five elements.
(iii) Let’s understand the
series problems by -
A B C D E F G H I J K L M
1 2 3 4 5 6 7 8 9 10 11 12 13
N O P Q R S T U V W X Y Z
14 15 16 17 18 19 20 21 22 23 24 25 26
Left element –
Left element = Left element
13th element from left – 8th
element from left
= 5th element from left is E.
Right element –
Right element = Right element
13th element from right –
8th element from right
= 5th element from right is
V.
These two answers E and V
are also opposite letters.
Left element +
Right element = Left element
13th element from left + 8th
element from right
= 21th element from left is U.
Right element + Left
element = Right element
13th element from right +
8th element from left
= 21th element from right is
F.
(iv) All these types of
questions are based on condition of left end or right end.
EX.1.
F @ 5 3 R $ J P E 1 H % I 8
4 B A W 2 U G 6 * 9 d Z N M © V
Q.1. Which of the following element is 18th from the left
end ?
(1) % (2) I (3) Q (4)
1 (5) None of these
SOLUTION
Short trick:
F @ 5 3 R / $ J P E 1 / H %
I 8 4 / B 8 A W 2 / U G 6 * 9 /
d Z N M © / V
13th from the left end is I.
Hence option (2) is correct.
Q.2. Which of the following is the 10th to the left of the 18th from the
left end of the above arrangement?
(1) J (2) E (3) A (4)
P (5)
None of these
SOLUTION
Short trick:
F @ 5 3 R / $ J P E 1 / H %
I 8 4 / B 8 A W 2 / U G 6 * 9 / d Z N M © / V
18th from the left –10th
from the left = 8th from the left.
Eighth element from the left
end is P.
Hence option (4) is correct.
Q.3. Four of the following
five are alike in a certain way based on their position in the above
arrangement hence form a group. Which is the one does not belong to that group?
(1) $ E P
(2) H 8 I (3) 8 8 B
(4) J 1 % (5) 6 d 9
SOLUTION
F @ 5 3 R $ J P E 1 H % I 8
4 B 8 A W 2 U G 6 * 9 d Z N M © V
In option (1) – Two elements
are between $ and E.
No element is between E and P.
In option (2) – Two elements
are between H and 8.
No element is between 8 and I.
In option (3) – Two elements
are between 6 and d.
No element is between d and B.
In option (4) – Two elements
are between J and 1.
One element is between 8 and %.
In option (5) – Two elements
are between J and 1.
One
element is between 8 and 9.
Hence option (4) is correct.
THANKS
