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SSC GD & MTS Quiz : Quantitative Aptitude | 16-01-2022

Swati Mahendras







Dear Readers,

As SSC GD & MTS notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of quizzes are based on the latest pattern of the SSC GD & MTS examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.



Q. 1. A part of sum of Rs. 10000 is lent at 8% and the remaining sum at 10% per annum. If the average rate of interest is 9.2%, then the two parts are -

10000 рд░ू. рдХा рдПрдХ рднाрдЧ 8% рдХी рд╡ाрд░्рд╖िрдХ рджрд░ рд╕े рдЙрдзाрд░ рджिрдпा рдЧрдпा рд╣ै рдФрд░ рд╢ेрд╖ рдзрди 10% рдХी рд╡ाрд░्рд╖िрдХ рджрд░ рдкрд░। рдпрджि рдм्рдпाрдЬ рдХी рдФрд╕рдд рджрд░ 9.2% рд╣ै, рддो рджो рднाрдЧ рд╣ै-

(A) Rs. 6000

(B) Rs. 8000

(C) Rs. 6400

(D) Rs. 6600

Q. 2. A and B can complete a piece of work in 12 and 18 days respectively. A begin to do the work and they work alternatively one at a time for one day each. The whole work will be completed in-

A рдФрд░ B рдПрдХ рдХाрдо рдХो рдХ्рд░рдорд╢ः 12 рдФрд░ 18 рджिрдиों рдоें рдХрд░ рд╕рдХрддे рд╣ै। A рдХाрдо рдХी рд╢ुрд░ूрдЖрдд рдХрд░ рд╡े рджोрдиों рдПрдХाрди्рддрд░ рдХ्рд░рдо рдоें рдХाрд░्рдп рдХрд░рддे рд╣ै। рдкूрд░ा рдХाрд░्рдп рд╕рдоाрдк्рдд рд╣ोрдЧा-

(A) 14 (1/3)

(B) 15 (2/3)

(C) 16 (1/3)

(D) 18 (2/3)

Q. 3. The speed of a motor boat is that of the current of water as 36:5. The boat goes along with the current in 5 hours 10 minutes. It will come back in -

рдПрдХ рдоोрдЯрд░рдмोрдЯ рдХी рдЪाрд▓, рдкाрдиी рдХे рдк्рд░рд╡ाрд╣ рдХे рд╕ाрдкेрдХ्рд╖ 36: 5 рд╣ै। рдмोрдЯ рдзाрд░ा рдХी рджिрд╢ा рдоें 5 рдШрдг्рдЯे 10 рдоिрдирдЯ рддрдХ рдЬाрддी рд╣ै। рдпрд╣ рд╡ाрдкрд╕ рдЖрдпेрдЧी-

(A) 5 hours 50 minutes/5 рдШंрдЯे 50 рдоिрдирдЯ

(B) 6 hours/6 рдШंрдЯे

(C) 6 hours 50 minutes/6 рдШंрдЯे 50 рдоिрдирдЯ

(D) 12 hours 10 minutes/12 рдШंрдЯे 10 рдоिрдирдЯ

Q. 4. From a series of 50 observations, an observation with value 45 is dropped, but the mean remains the same. What was the mean of 50 observations?

50 рдк्рд░ेрдХ्рд╖рдгों рдХी рдПрдХ рд╢्рд░ेрдгी рдоें, рдПрдХ рдк्рд░ेрдХ्рд╖рдг рдЬिрд╕рдХा рдоाрди 45 рдеा рдХो рд╣рдЯा рджेрдиे рдкрд░ рднी рдоाрди рд╡рд╣ी рд░рд╣рддा рд╣ै рддो 50 рдк्рд░ेрдХ्рд╖рдгों рдХा рдоाрдз्рдп рдХ्рдпा рдеा?

(A) 50

(B) 49

(C) 45

(D) 40

Q. 5. Amit scored 189 marks in Science, 156 marks in Hindi and 72 marks in Mathematics. The maximum marks of Science are 210, Hindi is 180 and Mathematics is 110. What percent of marks did Amit score overall?

рдЕрдоिрдд рдиे рд╡िрдЬ्рдЮाрди рдоें 189 рдЕंрдХ, рд╣िрди्рджी рдоें 156 рдЕंрдХ рдФрд░ рдЧрдгिрдд рдоें 72 рдЕंрдХ рдк्рд░ाрдк्рдд рдХिрдпे। рд╡िрдЬ्рдЮाрди рдоें рдЕрдзिрдХрддрдо 210 рд╣ै, рд╣िрди्рджी рдоें 180 рдФрд░ рдЧрдгिрдд рдоें 110 рд╣ै, рддो рдЕрдоिрдд рдХो рдХिрддрдиे рдк्рд░рддिрд╢рдд рдЕंрдХ рдк्рд░ाрдк्рдд рд╣ुрдпे?

(A) 82.8

(B) 84.4

(C) 83.4

(D) 84.2

Q. 6. Find the amount on which the difference of simple interest and compound interest compounded half - yearly will be Rs.122 at the rate of 10% in 1 (1/2) years?

рд╡рд╣ рд░ाрд╢ि рдЬ्рдЮाрдд рдХीрдЬिрдпे рдЬिрд╕ рдкрд░ 1 (1/2) рд╡рд░्рд╖ों рдоें 10% рд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рдХी рджрд░ рд╕े рд╕ाрдзाрд░рдг рдм्рдпाрдЬ рдФрд░ рдЪрдХ्рд░рд╡ृрдж्рдзि рдм्рдпाрдЬ рдЬोрдХि рдЕрд░्рдж्рдзрд╡ाрд░्рд╖िрдХ рд░ूрдк рд╕े рдЙрдкрдЪрдпिрдд рд╣ोрддा рд╣ै, рдХा рдЕंрддрд░ 122 рд░ु. рд╣ै ?

(A) Rs. 20000

(B) Rs. 18000

(C) Rs. 16000

(D) Rs. 14000

Q. 7. What will be the amount of the compound interest on a certain sum for three years, if simple interest on the same sum for the same time period at the rate of 10% p.a. is 1500?

рдХिрд╕ी рдзрдирд░ाрд╢ि рдкрд░ рддीрди рд╡рд░्рд╖ों рдоें рдЪрдХ्рд░рд╡ृрдж्рдзि рдм्рдпाрдЬ рдХ्рдпा рд╣ोрдЧा рдпрджि рдЙрд╕ी рдзрдирд░ाрд╢ि рдкрд░ рдЙрд╕ी рд╕рдордпाрд╡рдзि рдХी рд▓िрдП 10% рд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рдХी рджрд░ рд╕े рд╕ाрдзाрд░рдг рдм्рдпाрдЬ 1500 рд░ु. рд╣ै?

(A) Rs. 1645

(B) Rs. 1655

(C) Rs. 1600

(D) Rs. 1555

Q. 8. A shopkeeper bought an article marked at Rs. 22800 at two successive discounts of 15% and 20%. He spent Rs. 1064 on transportation and sold the article for Rs. 20710. Then, what was the profit percentage of the shopkeeper?

рдПрдХ рджुрдХाрдирджाрд░ рдиे рд░ु. 22800 рдЕंрдХिрдд рдоूрд▓्рдп рд╡ाрд▓ी рдПрдХ рд╡рд╕्рддु рдХो рдХ्рд░рдорд╢ः рджो рдХ्рд░рдоाрдЧрдд 15% рдФрд░ 20% рдХी рдЫूрдЯों рдкрд░ рдЦрд░ीрджा । рдЙрд╕рдиे 1064 рд░ु. рдЗрд╕рдХे рдкрд░िрд╡рд╣рди рдкрд░ рдЦрд░्рдЪ рдХрд░ рджिрдП рдФрд░ рдЗрд╕े 20710 рд░ु. рдоें рдмेрдЪा рддो рджुрдХाрдирджाрд░ рдж्рд╡ाрд░ा рдк्рд░ाрдк्рдд рдХिрдпा рдЧрдпा рд▓ाрдн рдк्рд░рддिрд╢рдд рдХिрддрдиा рд╣ै?

(A) 25%

(B) 30%

(C) 35%

(D) 20%

Q. 9. If perimeter of a square and rectangle is equal. If length and breadth of rectangle are 12 cm and 10 cm respectively. The area of square is what % more than that of rectangle?

рдпрджि рдПрдХ рд╡рд░्рдЧ рдФрд░ рдЖрдпрдд рдХा рдкрд░िрдоाрдк рдмрд░ाрдмрд░ рд╣ै । рдпрджि рдЖрдпрдд рдХी рд▓рдо्рдмाрдИ рдФрд░ рдЪौрдб़ाрдИ рдХ्рд░рдорд╢: 12 рд╕ेрдоी рдФрд░ 10 рд╕ेрдоी рд╣ै । рд╡рд░्рдЧ рдХा рдХ्рд╖ेрдд्рд░рдлрд▓ рдЖрдпрдд рдХी рддुрд▓рдиा рдоें рдХिрддрдиे % рдЕрдзिрдХ рд╣ै?

(A) 0.80%

(B) 0.73%

(C) 0.93%

(D) 0.83%

Q. 10. A sum of Rs. 7500 is to be divided among 5 men, 6 women and 8 boys. If the share of the ratio of the each man woman and boys are in the ratio 10: 7: 1. The share of one woman will be-

рдПрдХ рд░ाрд╢ि 7500 рд░ू. рдХो 5 рдкुрд░ूрд╖ों, 6 рдорд╣िрд▓ाрдУं рдФрд░ 8 рд▓реЬрдХों рдЗрд╕рдк्рд░рдХाрд░ рдмॉрдЯा рдЬाрддा рд╣ै рдХि рдк्рд░рдд्рдпेрдХ рдХो 10: 7: 1 рдХे рдЕрдиुрдкाрдд рдоें рдк्рд░ाрдк्рдд рд╣ो рддों рдПрдХ рдорд╣िрд▓ा рдХा рднाрдЧ рдХिрддрдиा рд╣ोрдЧा?

(A) Rs. 575

(B) Rs. 625

(C) Rs. 525

(D) Rs. 550

Answer key:-

1. Sol. (A)

Using method of alligation/рдоिрд╢्рд░рдг рдХी рд╡िрдзि рд╕े,

8%              10%

         9.2%

0.8%            1.2%

First part/рдкрд╣рд▓ा рднाрдЧ = (0.8/ 2) × 10000 = Rs. 4000

Second part/рджूрд╕рд░ा рднाрдЧ = (10000 – 4000) = Rs. 6000

2. Sol. (A)


A …………. 12           3

                          36

B …………. 18          2

work done in 2 days/2 рджिрди рдоें рдХिрдпा рдЧрдпा рдХाрд░्рдп = 5 units/рдоाрдд्рд░рдХ

Number of cycles/рдЪрдХ्рд░ों рдХी рд╕ंрдЦ्рдпा = 36 ÷ 5 = 7 cycles/рдЪрдХ्рд░

Remaining work/рд╢ेрд╖ рдХाрд░्рдп = 1 unit/рдоाрдд्рд░рдХ

Time taken to do this 1 unit of work/рдЗрд╕ 1 рдоाрдд्рд░рдХ рдХाрд░्рдп рдХो рдкूрд░ा рдХрд░рдиे рдоें рд▓िрдпा рдЧрдпा рд╕рдордп
= (1/3) days/рджिрди

Total time to complete the work/рдХाрд░्рдп рдХो рдкूрд░ा рдХрд░рдиे рдоें рд▓िрдпा рдЧрдпा рдХुрд▓ рд╕рдордп
= 14 (1/3) days/рджिрди

3. Sol. (C)

Let the speed of motor boat be 36 km. /hr. and speed of current 5x km. /hr.

рдоाрдиा рдПрдХ рдоोрдЯрд░ рдиाрд╡ рдХी рдЪाрд▓ 36 рдХिрдоी. /рдШंрдЯा рдФрд░ рдзाрд░ा рдХी рдЪाрд▓ 5x рдХिрдоी./рдШंрдЯा рд╣ै ।

Distance/рджूрд░ी = 5 hours 10 minute/5 рдШंрдЯे 10 рдоिрдирдЯ × (36x + 5x)

= [(41x × 31)/ 6] km./рдХिрдоी.

Rate of upstream/рдКрд░्рдз्рд╡рдк्рд░рд╡ाрд╣ рдХी рджрд░ = 36x – 5x = 31 x

Time taken/рд▓िрдпा рдЧрдпा рд╕рдордп = [{41x × (31/6)}/ (31x)] = 41/6 hours/рдШंрдЯे

= 6 hours 50 minutes/6 рдШंрдЯे 50 рдоिрдирдЯ

4. Sol. (C)

Let the mean of 50 observations/рдоाрдиा 50 рдк्рд░ेрдХ्рд╖рдгों рдХा рдоाрдз्рдп = x

then/рддो, 50 × x = (50 – 1) × x + 45

x = 45

5. Sol. (C)

Total percentage of marks/рдЕंрдХों рдХा рдХुрд▓ рдк्рд░рддिрд╢рдд

= [(189 + 156 + 72)/ (210 + 180 + 110)] × 100 = (417/500) × 100 = 83.4%

6. Sol. (C)

P = 122 × (100/5)2 × {100/ (5 + 300)}

= Rs.16000

7. Sol. (B)

P = [(1500 × 100)/ (10 × 3)] = 5000

C.I. = 5000 [{1 + (10/100)}3 – 1]

= 5000 [(11/10)3 – 1]

= 5000 × (331/1000) = Rs.1655

8. Sol. (A)

Marked price of the article/рд╡рд╕्рддु рдХा рдЕंрдХिрдд рдоूрд▓्рдп = Rs./рд░ु.22800

Cost price of the article/рд╡рд╕्рддु рдХा рдХ्рд░рдп рдоूрд▓्рдп = [{22800 – 22800 × (15/100)} × (80/100)]
= Rs. / рд░ु. 15504

Actual cost price/рд╡ाрд╕्рддрд╡िрдХ рдХ्рд░рдп рдоूрд▓्рдп = 15504 + 1064 = Rs.16568

Profit/рд▓ाрдн % = [{(20710 – 16568)/ 16568} × 100] = 25%

9. Sol. (D)

Side of a square/рдПрдХ рд╡рд░्рдЧ рдХी рднुрдЬा = {2 (12 + 10)}/ 4 = 11

Required/рдЕрднीрд╖्рдЯ % = [{(121 – 120)/ 120} × 100] = 0.83%

10. Sol. (C)

Ratio/рдЕрдиुрдкाрдд = 10 × 5: 7 × 6: 1 × 8

= 25: 21: 4

Sum of ratios/рдЖрдиुрдкाрддिрдХ рдпोрдЧ = 25 + 21 + 4 = 50

6 women's share/6 рдорд╣िрд▓ाрдУं рдХा рд╣िрд╕्рд╕ा = (21/50) × 7500 = Rs. 3150

1 women's share/1 рдорд╣िрд▓ा рдХा рд╣िрд╕्рд╕ा = 3150/6 = Rs.525

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