Quantitative Aptitude Quiz For SBI / RBI Main Exam | 23-05-2020

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Mahendras has started special quizzes for SBI / RBI Main Exam so that you can practice more and more to crack the examination. This SBI / RBI Main Exam quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination. Here we are providing you important question of Quantitative aptitude for SBI / RBI Main Exam.

(1) If the compound interest accrued on an amount of Rs. 14500 in two years is Rs. 4676.25, what is the rate of interest p.c.p.a.?

यदि 14500 रू. की धनराशि पर 2 वर्षों में उपचित चक्रवृद्धि ब्याज 4676.25 रू. है। प्र.श.प्र.व. ब्याज की दर क्या है?

(1) 11%

(2) 9%

(3) 15%

(4) 18%

(5) 16%



(2) A boat goes 6 km against the current of the stream in 2 hours and goes 8 km along the current in half hour. How long will it take to go 28.5 km in stationary water?

एक नाव धारा के प्रवाह के विपरीत 6 किमी. की दूरी 2 घंटे में तय करती है और धारा के प्रवाह की दिशा में 8 किमी. की दूरी आधे घंटे में तय करती है। शांत जल में 28.5 किलोमीटर की दूरी तय करने के लिये इसे कितना समय लगेगा?

(1) 3 hours

(2) 8 hours

(3) 10 hours

(4) 13 hours

(5) 15 hours



(3) A mixture contains A and B in the ratio 2 : 5. 7 litres of mixture is replaced by 18 litres of A and the new ratio becomes 8 : 11 respectively. What is the amount of A present in the original mixture?
एक मिश्रण में A और B का अनुपात 2:5 है। 7 लीटर मिश्रण को A के 18 लीटर से प्रतिस्थापित कर दिया जाता है और नया अनुपात क्रमशः 8:11 हो जाता है।मूल मिश्रण में मौजूद A की मात्रा क्या है?

(1) 12 liters

(2) 16 liters

(3) 20 liters

(4) 24 liters

(5) 27 liters



(4) The circumference of two circles is 132 metres and 176 metres respectively. What is the difference between the area of the larger circle and the smaller circle?

दो वृत्तों की परिधि क्रमशः 132 मीटर तथा 176 मीटर है। बड़े तथा छोटे वृत्त के क्षेत्रफलों के बीच क्या अन्तर है?

(1) 1048 m2.

(2) 1076 m2.

(3) 1078 m2.

(4) 1090 m2.

(5) None of these



Q-(5-8) In each question two equations are provided. One of the basis of these you have to find out the relations between p and q.

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और इनके आधार पर p तथा q में संबंध ज्ञात कीजिए।

(5) I. 5p2 - 8p + 3 = 0 II. 2q2 - 7q + 5 = 0

(1) If p = q or relation cannot be find.

(2) If p > q

(3) If p < q

(4) If p > q

(5) If p < q


(6) I. 12p2- p = 1 II. 18q2 - 9q + 1 = 0

(1) If p = q or relation cannot be find.

(2) If p > q

(3) If p < q

(4) If p > q

(5) If p < q



(7) I. 8p2 - 10p + 3 = 0 II. 2q2 + 5q + 3 = 0

(1) If p = q or relation cannot be find.

(2) If p > q

(3) If p < q

(4) If p > q

(5) If p < q



(8) I. p2 - 6p + 8 = 0 II. 3q2 - 10q + 7 = 0

(1) If p = q or relation cannot be find.

(2) If p > q

(3) If p < q

(4) If p > q

(5) If p < q


Q-(9-10) Find the wrong number in the following number series.

निम्नलिखित संख्या श्रृंखला में गलत संख्या का पता लगाइये।

(9) 27 29 38 61 105 178 284

(1) 29

(2) 61

(3) 38

(4) 27

(5) 178



(10) 400 450 350 375 325 330.5 312.5

(1) 330.5

(2) 450

(3) 400

(4) 375

(5) 325

Answer Key-

Q-(1) Sol-(3)

Required answer=15%

Q-(2) Sol-(1)
Speed upstream = 6/2 = 3, speed downstream = 8/(1/2) = 16
Speed of boat =(3+16)/2 = 9.5 km/hr
So time in still water = 28.5/9.5 = 3 hours

Q-(3) Sol-(4)

A = 2x, B = 5x
After 7 litres draw out:
A = 2x – (2/7) x 7 = 2x – 2 , B = 5x – (5/7) x 7 = 5x – 5
After 18 liter of A put back, A = (2x – 2) + 18 = 2x +16
So (2x+16) ÷ (5x – 5) = 8/11
Solve, x = 12
So A = 2x = 2 x 12 = 24 liters

Q-(4) Sol-(3)

Required answer=1078 m3

Q-(5) Sol-(5)
5p2 - 5p –3p + 3 =0
5p (p – 1) – 3 (p – 1) = 0
P = 1, 3/5
2q2 – 5q – 2q + 5 = 0
q (2q– 5)–1 (2q – 5)
q =5/2 ,1
q > p

Q-(6) Sol-(1)

P=1/3, 1/4

1/3,1/6

Relationship cannot be established

Q-(7) Sol-(3)

8p2 – 10 p + 3 = 0
8p2 – 6p – 4p + 3 = 0
2p (4p – 3) – (4p – 3)
p = 3/4,1/2
2q2 + 5q + 3 = 0
2q2 + 3q + 2q + 3 = 0
q (2q + 3) +1 (2q +3) = 0
q =3/2 ,1

Q-(8) Sol-(1)

p2 – 4p – p+ 8 = 0
p (p – 4) – 2p (p – 4) = 0
p = 4 ,2
3q2 – 10 q + 7 = 0
3q2 –7q – 3q + 7 = 0
q (3q– 7)– 1(3q – 7) = 0
q = 7/3,1
Relationship can't be determined

Q-(9) Sol-(5)

27 29 38 61 105 177 284

Q-(10) Sol-(1)

400 450 350 375 325 337.5 315.5