Quantitative Aptitude Quiz For SBI / RBI Main Exam | 11-05-2020

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Mahendras has started special quizzes for SBI / RBI Main Exam so that you can practice more and more to crack the examination. This SBI / RBI Main Exam quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination. Here we are providing you important question of Quantitative aptitude for SBI / RBI Main Exam.




Q-(1-5) What should come in place of the question mark (?) in the following question?

निम्न प्रश्न में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आयेगा ?

(1) 4900.48 = 24.7 × 15.5 × ?
(1) 19.2

(2) 11.6

(3) 10.5

(4) 12.8

(5) 14.4


(2) 566 × 35 × 8 = ?

(1) 154880

(2) 158480

(3) 158840

(4) 168480

(5) 168840


(3) [1652÷75×12]÷36=?2
(1) 7

(2) 9

(3) 11

(4) 13

(5) 17

(4) 338×?1/2=15210

(1) 2000

(2) 3000

(3) 2025

(4) 3025

(5) 5025


(5) [48×4–13×12]÷(25÷5×2)=?
(1) 3.8

(2) 6.4

(3) 3.4

(4) 3.6

(5) 4.8

Q-(6-10) In each of the following question, a question is followed by information given in two statement named as Quantity-I (Q1) and Quantity –II (Q2). You have to study the information and compare the value derived from Quantity-I and Quantity-II. Then answer -

निम्नलिखित प्रश्नों में प्रत्येक प्रश्न के लिए कुछ सूचना एवं दो कथन परिमाण- I (Q1) और परिमाण- II (Q2) के रूप में दी गयी हैं। आप प्रश्न सहित सूचना का अध्ययन कर परिमाण- I और परिमाण- II से प्राप्त मानों की तुलना कीजिये और उत्तर दीजिये –

(6) Find the percentage of girls in the class this year.
Quantity I: This year the percentage of boys in the class is 60%.
Quantity II: Last year out of the 300 students, 50% was boys and this year the number of boys are increased by 10% but total students remains same.

इस वर्ष कक्षा में लड़कियों का प्रतिशत ज्ञात कीजिये ।

मात्रा I: इस वर्ष कक्षा में लड़कों का प्रतिशत 60% है।
मात्रा II: पिछले साल 300 छात्रों में से, 50% लड़के थे और इस वर्ष लड़कों की संख्या में 10% की वृद्धि हुई है, लेकिन कुल मिलाकर छात्रों की संख्या समान है।

(1) Quantity I > Quantity II

(2) Quantity I < Quantity II

(3) Quantity I = Quantity II

(4) Quantity I > Quantity II

(5) Quantity I < Quantity II


(7) What is the age of Anushika?
Quantity I: Anushika is 3 years younger than Tushar and the ratio of their ages is 7: 8.
Quantity II: Average age of N and Anushika is 25 years and N is 2 years older than Anushika.

अनुषिका की उम्र क्या है?

मात्रा I: अनुषिका तुषार से 3 साल छोटी है और उनकी उम्र का अनुपात 7: 8 है।
मात्रा II: N और अनुषिका की औसत आयु 25 वर्ष है और N, अनुषिका से 2 वर्ष बड़ा है।

(1) Quantity I > Quantity II

(2) Quantity I = Quantity II

(3) Quantity I < Quantity II

(4) Quantity I < Quantity II

(5) Quantity I > Quantity II


(8) Quantity I: Speed of boat in still water, if a man can travel 54 km downstream in 9 hours and 40 km upstream in 10 hours.

Quantity II: Speed of boat in still water, if a man can travel 45 km downstream in 9 hours and the speed of stream is 1 kmph.

. मात्रा I: स्थिर पानी में नाव की गति, यदि कोई व्यक्ति 9 घंटे में 54 किमी अनुप्रवाह में और 10 घंटे में 40 किमी ऊर्ध्वप्रवाह में यात्रा कर सकता है।

मात्रा II: स्थिर पानी में नाव की गति, यदि कोई व्यक्ति 9 घंटे में 45 किमी अनुप्रवाह में यात्रा कर सकता है और धारा की गति 1 किमी प्रति घंटा है।

(1) Quantity I < Quantity II

(2) Quantity I > Quantity II

(3) Quantity I > Quantity II

(4) Quantity I < Quantity II

(5) Quantity I = Quantity II


(9) What is the area of the rectangle?

Quantity I: The area of the rectangle is equal to the area of the square whose side is 24 cm.
Quantity II: The perimeter of the rectangle is 88cm, if the ratio of the length and the breadth of the rectangle is 6 : 5.

आयत का क्षेत्रफल क्या है?

मात्रा I: आयत का क्षेत्रफल उस वर्ग के क्षेत्रफल के बराबर है जिसकी भुजा 24 सेमी है।
मात्रा II: आयत की परिधि 88 सेमी है, यदि आयत की लंबाई और चौड़ाई का अनुपात 6: 5 है।

(1) Quantity I = Quantity II

(2) Quantity I < Quantity II|

(3) Quantity I < Quantity II

(4) Quantity I > Quantity II

(5) Quantity I > Quantity II


(10) Amazon listed two headphones for Rs. 476. One of the headphones was sold at a loss of 25% and the other at a gain of 29% and the company found that each headphone was sold at the same price.

Quantity I: The cost price of the headphone which was sold at 29% profit.
Quantity II: The selling price of the headphone which was sold at 25% loss.

अमेज़न ने दो हेडफोन जो रु. 476 में अंकित थे, हेडफ़ोन में से एक को 25% की हानि पर बेचा गया था और दूसरे को 29% की बढ़त पर बेचा गया था और कंपनी ने पाया कि प्रत्येक हेडफोन एक ही कीमत पर बेचा गया था।

मात्रा I: हेडफ़ोन का लागत मूल्य जो 29% लाभ पर बेचा गया थी।

मात्रा II: हेडफ़ोन का बिक्री मूल्य जो 25% हानि पर बेचा गया थी।

(1) Quantity I > Quantity II

(2) Quantity I < Quantity II

(3) Quantity I > Quantity II

(4) Quantity I < Quantity II

(5) Quantity I = Quantity II or no relation can be established.


Answer Key-

Q-(1) Sol-(4)

4900.48 = 24.7 × 15.5 × ?

? = 12.8

Q-(2) Sol-(2)

? = 158480

Q-(3) Sol-(3)
[27225 ÷ 75 × 12] ÷ 36 = (?)2

[363 × 12] ÷ 36 = (?)2

4356 ÷ 36 = (?)2

121 = (?)2

? = 11

Q-(4) Sol-(3)
(?)1/2 = (15210/338)

(?)1/2 = 45

? = 2025

Q-(5) Sol-(4)

?=3.6

Q-(6) Sol-(2)
Quantity I:

Because percentage of boys = 60%,
So the percentage of girls = 100 – 60% = 40%

Quantity II:

Last year,

Boys was 300 × 50% = 150, girls = 300 × 50% = 150

This year, because boys are increased by 10% and total students remain same.

Boys = 150 × 110% = 165, girls = 300 – 165 = 135
% of girls = 45%

Quantity I < Quantity II

Q-(7) Sol-(3)

Quantity I:
Let the age of Anushika = 7x, Tushar = 8x
8x – 7x = 3
x = 3
Age of Anushika = 7 × 3 = 21 years

Quantity II:
Total age of Anushika and N = 25 × 2 = 50 years
Let the age of Anushika = x, N = x + 2
x + x + 2 = 50
2x = 50 – 2
2x = 48
x = 24
Age of Anushika = 24 years

Quantity I < Quantity II

Q-(8) Sol-(3)

Quantity I:
Let speed of boat = x kmph, speed of stream = y kmph
upstream speed = x – y, downstream speed = x + y
x + y = 54/9 = 6 … (I)
x – y = 40/10 = 4 … (II)
Equation (I) + equation (II)
x = 5
Speed of boat = 5 kmph

Quantity II:
Let speed of boat = x kmph, speed of stream = 1 kmph
downstream speed = x + 1
45/9 = x + 1
5 – 1 = x
x = 4
Speed of boat = 4 kmph

Quantity I > Quantity II

Q-(9) Sol-(5)

Quantity I:
Area of the square = 24 × 24 = 576 cm2
Area of the square = Area of the rectangle
Area of the rectangle = 576 cm2

Quantity II:
Length of the rectangle = 6x, Breadth = 5x
Perimeter = 88
2 (l + b) = 88
6x + 5x = 44
11x = 44
x = 4
Length = 24 cm, breadth = 20 cm
Area of the rectangle = 24 × 20 = 480 cm2

Quantity I > Quantity II

Q-(10) Sol-(2)

Let the cost price of Quantity II be x.
Therefore, the cost price of Quantity I will be = (476 – x)

Quantity II Quantity I
Cost price x (476 – x)
Selling price x × 75/100 (476 – x) × 128/100
Now as both the SP’s are equal,

25x = (476 – x) × 43
or, 25x + 43x = 476 × 43
or, 68x = 476 × 43
or, x = 301
Quantity I: The cost price of the headphone at 29% profit = 476 – 301 = 175

Quantity II: Selling price of the headphone sold at 25% loss=225.75

Quantity I < Quantity II