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Quantitative Aptitude Quiz For SBI / RBI Main Exam | 27-04-2020

Priyanka Mahendras







Dear Readers,




Mahendras has started special quizzes for SBI / RBI Main Exam so that you can practice more and more to crack the examination. This SBI / RBI Main Exam quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination. Here we are providing you important question of Quantitative aptitude for SBI / RBI Main Exam.



(1) If the perimeter of an equilateral triangle is 35 more than the perimeter of square and the ratio of side of square to the side of triangle is 4:7. Find the area of square.


यदि एक समबाहु त्रिभुज का परिमाप एक वर्ग के परिमाप से 35 अधिक है तथा वर्ग की भुजा और त्रिभुज की भुजा का अनुपात 4 : 7 है तो वर्ग का क्षेत्रफल ज्ञात कीजिए-

(1) 729

(2) 841

(3) 1024

(4) 784

(5) None of these


(2) In to solutions of milk and water ratio of milk and water 5:3 and 5:1 respectively. If these two solutions are mixed together in ratio 2:1, what will be ratio of milk and water in resultant solution.


दो विलयन में दूध तथा पानी का अनुपात क्रमशः 5: 3 तथा 5: 1 है। यदि दोनों विलयनों को 2: 1 के अनुपात में मिलाया जाय तो परिणामी मिश्रण में दूध और पानी का क्या अनुपात होगा?

(1) 9 : 7

(2) 25 : 11

(3) 35 : 17

(4) 3 : 2

(5) None of these


(3) Four coins are tossed simultaneously. Find the probability of getting tails more than 2?

चार सिक्कों को एक साथ उछाला जाता है। 2 से अधिक पुच्छ प्राप्त करने की प्रायिकता ज्ञात कीजिए-

(1) 1/2

(2) 1/4

(3) 3/8

(4) 5/16

(5) None of these



(4) A and B can finish a work in 24 days and 36 days respectively. They started the work together but often few days A left and B finished the remaining work in 16 days. Find after how many days did A leave.

A और B किसी कार्य को क्रमशः 24 दिन तथा 36 दिन में समाप्त करते हैं। दोनों ने कार्यों को एक साथ प्रारम्भ किया लेकिन कुछ दिनों पश्चात् A कार्य छोड़कर चला गया तथा B ने शेष कार्य 16 दिनों में समाप्त किया। बताइये कितने दिनों पश्चात् A ने कार्य करना छोड़ दिया?

(1) 5 days

(2) 4 days

(3) 7 days

(4) 6 days

(5) None of these


(5) A boat can travel 14.4 km down stream in 40 minutes. If the speed of current is 1/5 of the speed of the boat in still water. Find the distance travelled by boat in 20 minutes upstream.

एक नाव अनुप्रवाह दिशा में 40 मिनट में 14.4 किमी की दूरी तय कर सकती है। यदि धारा की चाल शान्त जल में नाव की चाल की 1/5 है तो नाव द्वारा उर्ध्वप्रवाह दिशा में 20 मिनट में तय की गयी दूरी ज्ञात कीजिए-

(1) 3.6 km

(2) 5.2 km

(3) 6 km

(4) 4.8 km

(5) None of these


Q-(6-10) In the following questions two equations are given, you have to find the values of the variables and state the correct relationship-


निम्नलिखित प्रश्नों में दो समीकरण दिये गये है, चरों का मान ज्ञात कीजिए तथा सही सम्बन्ध स्थापित कीजिए।

(6) I. x2 + x - 12 = 0 

II. y2 - 7x + 12 = 0


(1) x>y

(2) x>y

(3) x
(4) x
(5) x = y or relationship can't be determined.


(7) I. 3x2 + 23x + 44 = 0 

II. 2y2 - 11y + 15 = 0


(1) x>y

(2) x>y

(3) x
(4) x
(5) x = y or relationship can't be determined.


(8) I. x2 - 26x + 165 = 0 

II. y2 - 20y + 99 = 0

(1) x>y

(2) x>y

(3) x
(4) x
(5) x = y or relationship can't be determined.


(9) I. x2 - 16x - 63 = 0 

II. y2 + y - 20 = 0


(1) x>y

(2) x>y

(3) x
(4) x
(5) x = y or relationship can't be determined.


(10) I. x3 = -700 

II. y3 = - 800


(1) x>y

(2) x>y

(3) x
(4) x
(5) x = y or relationship can't be determined.

Answer Key-

Q-(1) Sol-(4)

7x × 3 - 4x × 4
5x = 35 ? x = 7
Side of square = 4x 7 = 28
Area of square = 282 = 784

Q-(2) Sol-(2)


5 : 3 = 8] × 3 × 2 = 15 : 9
5 : 1 = 6] × 4 × 1 = 10 : 2
25 : 11

Q-(3) Sol-(5)
P(E)=5/16

Q-(4) Sol-(5)


Required answer=40/5=8 days

Q-(5) Sol-(1)

40 minute = 14.4
60 minute = 21.6 (downstream speed)
Now, 5x+x=21.6
x = 3.6
Again, Upstream speed
= 5x-x= 4x = 3.6 × 4 = 14.4
Required Answer=4.8 km

Q-(6) Sol-(4)

x = -4, 3 y = 3, 4 x < y

Q-(7) Sol-(3)
x=-3.67,-4

y=3,2.5

x
Q-(8) Sol-(2)

x = 15, 11 y = 9, 11
x > y

Q-(9) Sol-(5)

x = -7, 9 y = -5, 4

Q-(10) Sol-(1)


x = -8 (approx) y = -9 (approx)

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