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SSC CGL & CHSL Quiz : Quantitative Aptitude | 11 -01-2020

Durgesh Mahendras
SSC CGL & CHSL Quiz : Quantitative Aptitude | 11 -01-2020


As SSC CGL notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes is based on the latest pattern of the SSC CGL examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.



Q.1:- At what percent rate, compound interest compounded half yearly for a sum of Rs.80,000 become Rs. 88,200 in one year?

(1) 5% pa
(2) 10% pa
(3) 12% pa
(4) 15 % pa
Q.2:- If/ यदि  SSC-MATHS-11-1-2020 then find the value of/ का मान ज्ञात करें SSC-MATHS-11-1-2020?

(1) 13/4
(2) 3/4
(3)  7/12
(4)  5/12

Q.3:- Triangle ABC, angle SSC-MATHS-11-1-2020 AB = 16 cm, BC = 20 cm P is mid point of AC, Q is the foot of the perpendicular drawn from P on BC, are of triangle CPQ = ?

त्रिभुज ABC में ,  कोण A = 90, AB = 16 सेमी, BC = 20 सेमी, P, AC का मध्य बिंदु है, E , बिंदु P से BC पर डाले गए लांब का पाद है, त्रिभुज CPQ ?

(1)  8.32
(2) 6.64
(3) 7.64
(4) 8.64

Q.4:- If x be the smallest number which is divisible by 16, 24, 30, 36 and 45. If x be a perfect square number then what is the remainder when it is divided by 121.

यदि x एक छोटी से छोटी संख्या है जो 16, 24, 30, 36 और  45 से पुर्णतः विभाजित है. यदि x एक पूर्ण वर्ग है तो शेष क्या होगा यदि x को 121 से विभाजित किया जाये तो ?

(1) 101
(2) 115
(3) 91
(4) 90

Q.5:- A light house of 54SSC-MATHS-11-1-2020  m is standing above  the sea level, a boat is traveling towards light house. A man standing on the light house see the angle of depression to the boat changes from SSC-MATHS-11-1-2020 to SSC-MATHS-11-1-2020 .  and boat will take 5 sec to travel that distance. Find the speed of boat?

एक लाइट हाउस समुद्र तल से 54SSC-MATHS-11-1-2020 मी की उचाई पर खड़ा है, एक नाव लाइट हाउस की तरफ आ रही है .  एक आदमी जो लाइट हाउस पर  खड़ा है जो नाव को देख रहा है नाव का अवनमन कोण SSC-MATHS-11-1-2020 से  SSC-MATHS-11-1-2020 तक बदल जाता है और यह दुरी तय करने में उसको 5 सेकेंड मे तय करता है नाव की चाल ज्ञात करें?

(1) 21.0
(2) 10.8
(3) 21.6
(4) 8.1

Q.6. IfSSC-MATHS-11-1-2020, then find the value of x?

 यदि SSC-MATHS-11-1-2020 तो x का मान क्या होगा ?

(1) 3
(2) 1
(3) 2
(4) -1/3
Q.7  If a : b : c = 1 : 3 : 5 , what is the value of SSC-MATHS-11-1-2020?

यदि  a : b : c = 1 : 3 : 5 , तो  SSC-MATHS-11-1-2020 का मान क्या है ?

(1) 8/27
(2) 10/27
(3)  11/27
(4) 1/3

Q.8. If A, B and C can complete a piece of work in 20, 24 and 36 days respectively, how many days will they take to complete the work, If they work together?

यदि
A, B और C क्रमशः 20, 24 और 36 दिनों में एक काम पूरा कर सकते हैं, तो उन्हें काम पूरा करने में कितने दिन लगेंगे, अगर वे एक साथ काम करते हैं?

(1) SSC-MATHS-11-1-2020
(2) SSC-MATHS-11-1-2020
(3) SSC-MATHS-11-1-2020
(4) SSC-MATHS-11-1-2020

Q.9. The diagonal of the rhombus are respectively 4 cm and 12 cm. Its area (in cm2) is equal to ?

समचतुर्भुज का विकर्ण क्रमशः 4 सेमी और 12 सेमी है। इसका क्षेत्रफल (सेमी2 में) के बराबर है?


(1) 12
(2) 24
(3) 36
(4) 8

Q.10 For an examination of a practical based subjects, the total is marks is 100. The break-up for theory, practical, project, and viva voce is 40%, 30%, 20% and 10%. A candidate scored 80% in theory, 70% in practical, 60% in project and 50% in  viva voce. What was her aggregate percentage?

एक व्यावहारिक आधारित विषयों की परीक्षा के लिए, कुल अंक 100 हैं। सिद्धांत, व्यावहारिक, प्रोजेक्ट और मौखिक के लिए वितरण 40%, 30%, 20% और 10% है। एक उम्मीदवार ने सिद्धांत में 80%, प्रैक्टिकल में 70%, प्रोजेक्ट में 60% और मौखिक में 50% स्कोर किया। उसका कुल प्रतिशत क्या था?


(1) 70
(2) 72
(3) 68
(4) 67







Answer:-
1.Sol:- (2)
SSC-MATHS-11-1-2020
SSC-MATHS-11-1-2020
SSC-MATHS-11-1-2020
R = 10% pa
2. Sol:- (3)
SSC-MATHS-11-1-2020
SSC-MATHS-11-1-2020
After solving,
SSC-MATHS-11-1-2020
SSC-MATHS-11-1-2020 
3.Sol:- (4)
SSC-MATHS-11-1-2020
Triangle CAB and CQP are similar
Hence,
Angle CAB = angle CQP = 90
Angle ACB = angle QCP = SSC-MATHS-11-1-2020
From rule of similarity
SSC-MATHS-11-1-2020
After solving,
PQ = 4.8 c.m  and CQ = 3.6 cm
Area = (1/2) x 4.8 cm x 3.6 cm
Area = 8.64 cm x cm
4.Sol:-  (3)
LCM of 16, 24, 30, 36 and 45 = 720
So value of x = 3600 ( because x be the perfect square)
Remainder when 3600 is divided by 121 is 91
5.Sol:- (3)
SSC-MATHS-11-1-2020
SSC-MATHS-11-1-2020
AB = SSC-MATHS-11-1-2020
SSC-MATHS-11-1-2020
AC = 162 m
BC = SSC-MATHS-11-1-2020
Speed = 108/ 5 = 21.6 m/s
6. Sol. (2)
SSC-MATHS-11-1-2020
7. Sol. (3)
SSC-MATHS-11-1-2020
8. Sol. (1)
SSC-MATHS-11-1-2020
9. Sol. (2)
SSC-MATHS-11-1-2020

10. Sol. (1)
SSC-MATHS-11-1-2020

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