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# SSC Quiz : Quantitative Aptitude | 04- 10 - 19

Mahendra Guru

In SSC exam, quantitative Aptitude section is more scoring and easy, if you know the shorts tricks and formulas of all the topics. So, it is important to know the basic concepts of all the topics so you can apply the short tricks and solve the question with the new concepts in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz of quantitative Aptitude section helps you to analyse your preparation level for the upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exams like Insurance, SSC-MTS, SSC CPO, CGL, CHSL, State Level, and other Competitive exams.
So, here we will provide you a set of 10 questions of Quantitative Aptitude, important for SSC  exam.

Q. 1. Rs.21594 is divided between Rakesh and Anil such that Rakesh's share at the end of 9 years at the rate of 20% compounded annually is equal to the share of Anil at the end of the 11 years, then what is share of Rakesh?

(A) Rs.12744
(B) Rs.9144
(C) Rs.9414
(D) Rs.12474

Q. 1. रु.21594 को राकेश और अनिल में इस प्रकार बांटा जाता है कि राकेश का 9 वर्ष में 20% वार्षिक चक्रवृद्धि ब्याज की दर से हिस्सा अनिल का 11 वर्ष में उसी ब्याज की दर से हिस्से के बराबर है, तो राकेश का हिस्सा क्या है ?

(A) रु.12744
(B) रु.9144
(C) रु.9414
(D) रु.12474

Q. 2. The angle of depression of the foot of a building from the top of a tower 66 m away is 30o. How high is the tower?

(A) 44 m.
(B)  m.
(C)  m.
(D) 36 m.

Q. 2. 66 मीटर दूर एक टावर के ऊपर से एक इमारत के पाद के अवनमन का कोण 30o है। टावर कितना ऊंचा है?

(A) 44 मी.
(B)  मी.
(C)  मी.
(D) 36 मी.

Q. 3. The ages of A and B five years ago, was 16 years and 30 years respectively. Then if the ratio of their ages will become 2 : 3 after n years, what is the value of n?

(A) 4
(B) 3
(C) 6
(D) 7

Q. 3. पाँच वर्ष पहले A और B की आयु क्रमशः 16 वर्ष और 30 वर्ष है | तो यदि n वर्षों बाद उनकी आयु में अनुपात 2 : 3 होता है, तो n का मान क्या है ?

(A) 4
(B) 3
(C) 6
(D) 7

Q. 4. The numbers p, q, r are respectively proportional to 2, 3, 5 and the sum of p, q and r is 80. If the number r is given by the equation r = mp – 8, then m is

(A) 6
(B) 3/2
(C) 5/2
(D) 3

Q. 4. संख्याएं p, q, r क्रमशः 2, 3, 5 के समानुपाती हैं और p, q और r का योग 80 है | यदि संख्या r समीकरण r = mp – 8, से दी गयी हो, तो m है –

(A) 6
(B) 3/2
(C) 5/2
(D) 3

Q. 5. Ayushi and Aanchal together can do a work in 12 days. Aanchal and Vaishnavi together do it in 15 days. If Ayushi's efficiency is twice that of Vaishnavi, then the days required for Aanchal alone to finish the work is

(A) 60
(B) 20
(C) 25
(D) 15

Q. 5. आयुषी और आँचल एकसाथ मिलकर एक कार्य को 12 दिनों में कर सकती हैं | आँचल और वैष्णवी एकसाथ मिलकर इसे 15 दिनों में कर सकती हैं | यदि आयुषी की कार्यक्षमता वैष्णवी की दोगुनी हो, तो आँचल द्वारा अकेले कार्य को समाप्त करने में आवश्यक दिनों की संख्या है

(A) 60
(B) 20
(C) 25
(D) 15

Q. 6. If (x – 2) (x – p) = x2 – ax + 6, then the value of (a – p) is

(A) 0
(B) 1
(C) 3
(D) 2

Q. 6. यदि (x – 2) (x – p) = x2 – ax + 6, तो (a – p) का मान है

(A) 0
(B) 1
(C) 3
(D) 2

Q. 7. The ratio of difference between simple interest and compound interest of a certain sum of money for 2 years and for 3 years is 5: 16. Then rate of interest is

(A) 12%
(B) 15%
(C) 20%
(D) 25%

Q. 7. एक निश्चित धनराशि पर 2 वर्ष तथा 3 वर्ष के साधारण ब्याज और चक्रवृद्धि ब्याज के अन्तर में अनुपात 5: 16 है | ब्याज की दर है

(A) 12%
(B) 15%
(C) 20%
(D) 25%

Q. 8. The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of the two numbers is 2. Find the sum of sqaures of the two numbers.

(A) 196
(B) 52
(C) 100
(D) 64

Q. 9. Aafiya calculates her profit/loss percent on selling price. She realized that she was selling an article at 25% loss but when she increased selling price by 108 Rs. She gets a profit percent of 20%. Find the Cost price of Article.

(A) Rs.240
(B) Rs.275
(C) Rs.300
(D) Rs.360

Q. 9. आफिया अपना लाभ/हानि प्रतिशत विक्रय मूल्य पर निकालती है। उसने महसूस किया कि वह किसी वस्तु को 25% हानि पर बेच रही थी लेकिन जब उसने विक्रय मूल्य 108 रूपये बढ़ा दिया अब उसे 20% का लाभ हुआ । उस वस्तु का क्रय मूल्य ज्ञात कीजिए ।

(A) रु.240
(B) रु.275
(C) रु.300
(D) रु.360

Q. 10. The area of a square is equal to the area of a rectangle. The length of the rectangle is 5 cm more than the side of the square and its breadth is 3 cm. less than the side of the square. What is the perimeter of the rectangle? (A) 35 cm.
(B) 34 cm.
(C) 17 cm.
(D) 17.5 cm.

Q. 10. एक वर्ग का क्षेत्रफल एक आयत के क्षेत्रफल के बराबर है । आयत की लम्बाई वर्ग की भुजा की लम्बाई से 5 सेमी अधिक है और उसकी चौड़ाई वर्ग की भुजा से 3 सेमी. कम है । आयत का परिमाप क्या है?(A) 35 सेमी.
(B) 34 सेमी.
(C) 17 सेमी.
(D) 17.5 सेमी.

1. Sol. (A)
Let Rakesh's share = Rs.x
and Anil's share = Rs. (21594 – x)
According to the question,

2. Sol. (C)
tan 30o =

h =  m.

3. Sol. (D)
According to the question,

(21 + n) × 3 = (35 + n) × 2
63 + 3n = 70 + 2n
n = 7

4. Sol. (D)p: q: r = 2: 3: 5
Hence, p = 2x, q = 3x and r = 5x
p + q + r = 80
2x + 3x + 5x = 80
10x = 80, x = 8
p = 16, q = 24 and/और r = 40
From the given equation,
40 = m × 16 – 8
m = 3

5. Sol. (B)Ayushi + Aanchal …… 12                                                5 units of work per day
[L.C.M. of 12 and 15 = 60]
Aanchal + Vaishnavi ……15                                             4 units of work per day
According to the question,
Ratio between efficiency of Ayushi and Vaishnavi = 2: 1
Ayushi + Aanchal + Aanchal + Vaishnavi = 5 + 4
2 + 2 × Aanchal + 1 = 9
Aanchal = 3
Time taken by Aanchal to complete the work = 60 ÷ 3 = 20 days

6. Sol. (D) (x – 2) (x – p) = x2 – ax + 6
x2 – px – 2x + 2p = x2 – ax + 6
x2 – (p + 2) + 2p = x2 – ax + 6
On comparison both the sides, we get
p + 2 = a, 2p = 6
p + 2 = a, p = 3
3 + 2 = a, a = 5
Now, a – p = 5 – 3 = 2

7. Sol. (C)
On solving above, we get
r = 20%

8. Sol. (B) Product of the numbers = 24
xy = 24 ........ (I)
Difference of the numbers = 2
x – y = 2 ....... (II)
From (I) and (II), we get,
x = 6, y = 4
Required answer = 62 + 42 = 36 + 16 = 52

9. Sol. (A) Case – I:
S.P: C.P. = 4: 5 = 16: 20
Case – II:
S.P: C.P. = 5: 4 = 25: 20
According to the question,
25 – 16 = 108
9 = 108
20 = 240

10. Sol. (B) Let side of the square = a cm.
Breadth of the rectangle = (a – 3) cm.
Length of the rectangle = (a + 5) cm.
According to the question,
a2 = l
a2 = (a – 3) (a + 5)
a2 = a2 + 2a – 15
a = 15/2 = 7.5 cm.
Perimeter of the rectangle = 2 (l + b)
= 2 (4.5 + 12.5) = 34 cm.

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