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SSC CPO : Quantitative Aptitude Quiz | 10- 07 - 18

Mahendra Guru
SSC CPO : Quantitative Aptitude Quiz | 10- 07 - 18
In SSC exam, quantitative Aptitude section is more scoring and easy, if you know the shorts tricks and formulas of all the topics. So, it is important to know the basic concepts of all the topics so you can apply the short tricks and solve the question with the new concepts in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz of quantitative Aptitude section helps you to analyse your preparation level for upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exams like Insurance, SSC-MTS, SSC CPO, CGL, CHSL, State Level, and other Competitive exams.


Mahendra Guru also provides you important notes and study material for all subject and test through its website, Mahendra Guru App and YouTube channel apart from it Speed Test Portal. Most of these preparation products are also available for purchase on my shop. You can also visit Mahendras.org to get more information about our endeavour for your success. You can also study in details through our E-Mahendras Facebook and Mahendra Guru YouTube channel of Quantitative Aptitude.


Q.1. If the difference between exterior angles and interior angle of a polygon is 600, find the number of sides in the polygon?

рдпрджि рдПрдХ рдмрд╣ुрднुрдЬ рдХे рд╡ाрд╣ृрдп рдФрд░ рдЕंрддः рдХोрдгों рдХा рдЕрди्рддрд░ 600 рд╣ै, рдмрд╣ुрднुрдЬ рдоें рднुрдЬाрдУं рдХी рд╕ंрдЦ्рдпा рд╣ै-


(A) 4
(B) 5
(C) 6
(D) 7


Q.2. AB is a chord of a circle whose centre is O. P is a point on the circle such that OP http://onlinespeedtest.mahendras.org/Images/13865459540823.jpg AB and OP intersects AB at a point M. If AB = 8 cm. and MP = 2 cm, then the radius of the circle is - 


AB рдПрдХ O рдХेрди्рдж्рд░ рд╡ाрд▓े рд╡ृрдд्рдд рдХी рдЬीрд╡ा рд╣ै। рдПрдХ рдмिрди्рджु P рд╡ृрдд्рдд рдкрд░ рдЗрд╕ рдк्рд░рдХाрд░ рд╣ै рдХि OPhttp://onlinespeedtest.mahendras.org/Images/13865459540823.jpg AB рдФрд░ OP, AB рдХो рдПрдХ рдмिрди्рджु M рдкрд░ рдк्рд░рддिрдЪ्рдЫेрджिрдд рдХрд░рддा рд╣ै। рдпрджि AB = 8 рд╕ेрдоी. рдФрд░ MP = 2 рд╕ेрдоी. рд╣ो, рддो рд╡ृрдд्рдд рдХी рдд्рд░िрдЬ्рдпा рд╣ै- 


(A) 3 cm/рд╕ेрдоी.
(B) 4 cm/рд╕ेрдоी.
(C) 6 cm/рд╕ेрдоी.
(D) 5.5 cm/рд╕ेрдоी.


Q.3. In a parallelogram ABCD, bisectors of  A and B meet at point O, then AOB is equal to -


рдПрдХ рд╕рдоाрди्рддрд░ рдЪрддुрд░्рднुрдЬ ABCD рдоें A рдФрд░ B рдХे рдж्рд╡िрднाрдЬрдХ O рдкрд░ рдоिрд▓рддे рд╣ै рддो, AOB рдмрд░ाрдмрд░ рд╣ै -


(A) 85o
(B) 90o
(C) 110o
(D) 130o


Q.4. ABCD is a rectangle of dimensions 8 units and 6 units. AEFC is a rectangle drawn in such a way that diagonal AC of the first rectangle is one side and side opposite to it, is touching the first rectangle at D. What is the ratio of the area of rectangle ABCD to that of AEFC?


ABCD рдПрдХ рдЖрдпрдд рд╣ै, рдЬिрд╕рдХी рд▓рдо्рдмाрдИ, рдЪौреЬाрдИ рдХ्рд░рдорд╢ः 8 рдФрд░ 6 рдЗрдХाрдЗрдпाँ рд╣ैं। AEFC рдПрдХ рдРрд╕ा рдЖрдпрдд рдмрдиाрдпा рдЧрдпा рд╣ै, рдЬिрд╕рдХी рдПрдХ рднुрдЬा рдкрд╣рд▓े рдЖрдпрдд рдХा рд╡िрдХрд░्рдг AC рд╣ै рддрдеा рдЗрд╕рдХे рд╕ाрдордиे рд╡ाрд▓ी рднुрдЬा рдкрд╣рд▓े рдЖрдпрдд рдХो D рдкрд░ рдЫूрддी рд╣ै। рдЖрдпрдд ABCD рдХे рдХ्рд╖ेрдд्рд░рдлрд▓ рдХा рдЖрдпрдд AEFC рдХे рдХ्рд╖ेрдд्рд░рдлрд▓ рд╕े рдЕрдиुрдкाрдд рдХ्рдпा рд╣ै?


(A) 2
(B)
(C) 1
(D)


Q.5. A field is 125 m. long and 15 m. wide. A tank 10 m. × 7.5 m. × 6 m. was dug in it and the earth thus dug out was spread equally on the remaining field. The level of the field thus raised is equal to which one of the following?


рдПрдХ рдЦेрдд рдХी рд▓рдо्рдмाрдИ 125 рдоी. рдФрд░ рдЪौреЬाрдИ 15 рдоी. рд╣ै। рдЗрд╕ рдЦेрдд рдоें 10 рдоी. × 7.5 рдоी. × 6 рдоी. рдХा рдЧрдб्рдвा рдЦोрджा рдЧрдпा рдФрд░ рдЗрд╕рд╕े рдиिрдХाрд▓ी рдЧрдИ рдоिрдЯ्рдЯी рдХो рдЦेрдд рдХे рд╢ेрд╖ рднाрдЧ рдоें рд╕рдоाрди рд░ूрдк рд╕े рдлैрд▓ा рджिрдпा рдЧрдпा। рдЦेрдд рдХा рддрд▓ рдиिрдо्рдирд▓िрдЦिрдд рдоें рд╕े рдХिрд╕рдХे рдмрд░ाрдмрд░ рдКँрдЪा рд╣ो рдЬाрддा рд╣ै?


(A) 15 cm./рд╕ेрдоी.
(B) 20 cm./рд╕ेрдоी.
(C) 25 cm./рд╕ेрдоी.
(D) 30 cm./рд╕ेрдоी.


Q.6. What is the total surface area of a one-side open cubical box of outer side of length 5 cm. and thickness 0.5 cm?


рдЙрд╕ рдШрдиाрдХाрд░ рдПрдХ рдУрд░ рд╕े рдЦुрд▓े рдмрдХ्рд╕े рдХा рд╕рдо्рдкूрд░्рдг рдкृрд╖्рда рдХ्рд╖ेрдд्рд░рдлрд▓ рдХ्рдпा рд╣ै, рдЬिрд╕рдХी рдмाрд╣्рдп рднुрдЬा рдХी рд▓рдо्рдмाрдИ 5 рд╕ेрдоी. рдФрд░ рдоोрдЯाрдИ 0.5 рд╕ेрдоी. рд╣ै?


(A) 125 cm.2/рд╕ेрдоी.2
(B) 214 cm.2/рд╕ेрдоी.2
(C) 180 cm.2/рд╕ेрдоी.2
(D) 205 cm.2/рд╕ेрдоी.2


Q.7. A solid metallic cube of edge 4 cm. is melted and recast into solid cubes of edge 1 cm. If x is surface area of the melted cube and y is the total surface area of all the cubes recast, then what is x: y?


4 рд╕ेрдоी. рднुрдЬा рд╡ाрд▓े рдПрдХ рдШрдиाрдХाрд░ рдзाрдд्рд╡िрдХ рдаोрд╕ рдХो рдкिрдШрд▓ाрдХрд░ 1 рд╕ेрдоी. рднुрдЬा рд╡ाрд▓े рдШрдиाрдХाрд░ рдаोрд╕ рдмрдиाрдП рдЬाрддे рд╣ैं। рдпрджि рдЧрд▓ाрдП рдЧрдП рдШрди рдХा рдкृрд╖्рда рдХ्рд╖ेрдд्рд░рдлрд▓ x рд╣ै рдФрд░ рдмрдиाрдП рд╕рднी рдаोрд╕ों рдХा рдХुрд▓ рдкृрд╖्рда рдХ्рд╖ेрдд्рд░рдлрд▓ y рд╣ै, рддो x: y рдХ्рдпा рд╣ै?


(A) 3: 1
(B) 1: 2
(C) 1: 4
(D) 4: 1


Q.8. A car made a trip of 300 km., covering the first 150 km. at the rate of 50 km./hr. and the second 150 km. at 40 km./hr. What was the average speed of the car in km./hr.?


рдПрдХ рдХाрд░ рдиे 300 рдХिрдоी. рдХी рдпाрдд्рд░ा, рдкрд╣рд▓े 150 рдХिрдоी. рдХो 50 рдХिрдоी./рдШं. рдФрд░ рдХी рдЧрддि рд╕े рдФрд░ рджूрд╕рд░े 150 рдХिрдоी. рдХो 40 рдХिрдоी./рдШं. рдХी рдЧрддि рд╕े рдЪрд▓рдХрд░ рдкूрд░ा рдХिрдпा | рдХाрд░ рдХी рдХिрдоी./рдШं. рдоें рдФрд╕рдд рдЧрддि рдХ्рдпा рдеी?


(A) 44.4/(рдХिрдоी./рдШं.)
(B) 33.3/(рдХिрдоी./рдШं.)
(C) 55.5/(рдХिрдоी./рдШं.)
(D) 66.6/(рдХिрдоी./рдШं.)


Q.9. A container is in the form of a right circular cylinder surmounted by a hemisphere of the same radius 15 cm. as the cylinder. If the volume of the container is 32400 ╧А cm3, then the height h of the container satisfies which one of the following?


рдПрдХ рдкाрдд्рд░ рдПрдХ рд▓рдо्рдм рд╡ृрдд्рддाрдХाрд░ рдмेрд▓рди рдХे рдКрдкрд░ рдПрдХ рдЧोрд▓ाрд░्рдж्рдз рдХे рдЖрдХाрд░ рдХा рд╣ै। рдЧोрд▓ाрд░्рдж्рдз рдХी рдд्рд░िрдЬ्рдпा рдФрд░ рдмेрд▓рди рдХी рдд्рд░िрдЬ्рдпा рд╕рдоाрди рд╣ै рдЬो рдХि 15 рд╕ेрдоी. рд╣ै। рдпрджि рдкाрдд्рд░ рдХा рдЖрдпрддрди 32400 ╧А рд╕ेрдоी3. рд╣ै, рддो рдкाрдд्рд░ рдХी рдКँрдЪाрдИ h рдиिрдо्рдирд▓िрдЦिрдд рдоें рд╕े рдХौрди-рд╕े рдПрдХ рдХो рд╕рди्рддुрд╖्рдЯ рдХрд░рддी рд╣ै?


(A) 135 cm. /рд╕ेрдоी. < h < 150 cm. /рд╕ेрдоी.
(B) 140 cm. /рд╕ेрдоी. < h < 147 cm. /рд╕ेрдоी.
(C) 145 cm. /рд╕ेрдоी. < h < 148 cm. /рд╕ेрдоी.
(D) 139 cm. /рд╕ेрдоी. < h < 145 cm. /рд╕ेрдоी.


Q.10. The sum of the age of a father and the age of his son is 75 years. If the product of their ages before 5 years was 750, then what is the present age of son?


рдПрдХ рдкिрддा рдХी рдЖрдпु рдФрд░ рдЙрд╕рдХे рдкुрдд्рд░ рдХी рдЖрдпु рдХा рдпोрдЧ 75 рд╡рд░्рд╖ рд╣ै। рдпрджि 5 рд╡рд░्рд╖ рдкрд╣рд▓े рдЙрдирдХी рдЖрдпु рдХा рдЧुрдгрдирдлрд▓ 750 рд╣ो, рддो рдкुрдд्рд░ рдХी рд╡рд░्рддрдоाрди рдЖрдпु рдХ्рдпा рд╣ै?


(A) 30 years/рд╡рд░्рд╖
(B) 55 years/рд╡рд░्рд╖
(C) 25 years/рд╡рд░्рд╖
(D) 20 years/рд╡рд░्рд╖


Answers:


1. Sol. (C) Exterior angle/рд╡ाрд╣्рдп рдХोрдг – Interior angle/рдЕрди्рддः рдХोрдг = 60o
                 
                 
                  180n – 720 = 60n
                  120n = 720
                  n = 6
2. Sol. (A)

AM = MB = 4
MP = 2
Let/рдоाрдиा OA = x
OP = OA = x
OM = (OP – MP) = (x – 2)
OA2 = OM2 + AM2
x2 = (x – 2)2 + 42
x = 3


3. Sol. (B) http://onlinespeedtest.mahendras.org/Images/138654496839413.jpg 


4. Sol. (C)

62 – x2 = 82 – (102 – x2)
36 – x2 = 64 – 100 – x2 + 20x
x = 3.6
AE = 4.8
Ratio of rectangle ABCD and rectangle AEFC/рдЖрдпрдд ABCD рдХा рдЖрдпрдд AEFC рд╕े рдЕрдиुрдкाрдд
= 8 × 6: 10 × 4.8 = 1: 1


5. Sol. (C) Area of ABEFGD/ABEFGD рдХा рдХ्рд╖ेрдд्рд░рдлрд▓ = 125 × 15 – 10 × 7.5 = 1800
                 
                  Let the level of the field be raised/рдоाрдиा рдЦेрдд рдХे рд╕्рддрд░ рдоें рд╡ृрдж्рдзि = h m./рдоी.
                  1800 × h = 10 × 7.5 × 6
                  h = = 25 cm./рд╕ेрдоी.


6. Sol. (D) The total surface area of a cube/рдПрдХ рдШрди рдХा рд╕рдо्рдкूрд░्рдг рдкृрд╖्рда рдХ्рд╖ेрдд्рд░рдлрд▓ = (6×52 – 52) (6×42 – 42)
                                                                     = 125 + 80
                                                                     = 205 cm.2/рд╕ेрдоी.2
7. Sol. (C) Volume of cube/рдШрди рдХा рдЖрдпрддрди = 43 = 64 cm/рд╕ेрдоी.3
                  Number of small cube/рдЫोрдЯे рдШрдиों рдХी рд╕ंрдЦ्рдпा = = 64
                  According to question/рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
                  x: y = 6 × 4 × 4: 6 × 1 × 64
                  x: y = 1: 4
8. Sol. (A) Average speed/рдФрд╕рдд рдЪाрд▓ =
                                                            = 44.4 km/hr./(рдХिрдоी./рдШं.)
9. Sol. (A) Let the height of the cylinder is a
                  Volume of the container =
                  32400 ╧А = 2250 ╧А + 225 ╧А a
                  a = 134 cm.
                  Height of the cylinder/рдмेрд▓рди рдХी рдКँрдЪाрдИ = 134 + 15 = 149 cm. /рд╕ेрдоी.
10. Sol. (D) Let present age of son be x/рдоाрдиा рдкुрдд्рд░ рдХी рд╡рд░्рддрдоाрди рдЖрдпु x рд╣ै।
                    (x – 5) (70 – x) = 750
                    x2 – 75x + 1100 = 0
                    (x – 55) (x – 20) = 0
                    (x – 55) (x – 20) = 0
                    x = 55, x = 20
                    Present age of son/рдкुрдд्рд░ рдХी рд╡рд░्рддрдоाрди рдЖрдпु = 20 years/рд╡рд░्рд╖

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