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SSC CGL & CHSL Quiz : Quantitative Aptitude | 17 -01-2020

Durgesh Mahendras
SSC CGL & CHSL Quiz : Quantitative Aptitude | 17 -01-2020


As SSC CGL notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes is based on the latest pattern of the SSC CGL examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.



Q.1:- LCM of 165, 176, 385, 495 is  K, is divided by HCF of 209, 418 , 539 and 319 leaves a quotient P what is the value of 12.5% of P

165, 176 , 385, और 495 का ल. स. प K है, को 209, 418 , 539 और 319 के म. स. प से विभाजित किया जाता है भागफल P आता है तो P का 12.5% क्या होगा ?

(1) 3720
(2) 630
(3) 5040
(4) 1260

Q.2:- An amount of Rs.X is distributed among A, B, C and D in such a way that ratio of amount of A and B is 8: 9. B and C is 2: 3, and C to D  is 9 : 13 if the difference between amount received by A and C is Rs.12650 find the value of x?

यदि x रुपये को A, B, C और D में इस प्रकार विभाजित किया जाता है की A और B के अंशो का अनुपात 8 : 9 है. B और C का 2:3 के अनुपात में और C और डD का अनुपात 9 : 13 है यदि A और C द्वायारा पायी गयी धन्राशिमे अंतर Rs.12650 तो X का मान ज्ञात करें?

(1) 125000
(2) 12500
(3) 11500
(4) 115000

Q.3:- A man is 11 m long is standing on H m high building if angle of depression from his eyes to a mile stone is 60 degree  and angle of elevation from mile stone to top of building is 45 degree then what is value of H?

एक 11 मी लंबा आदमी एक H मी उची इमारात पर खड़ा है यदि उसकी आँखों से एक मील के पत्थर का अवनमन कोण 60 अंश है और मील के पथर से इमारत के शीर्ष का उन्नयन कोण 45 अंश  है तो H का मान ज्ञात करें?

(1)SSC-CGL-MATHS-17-01-2020
(2) SSC-CGL-MATHS-17-01-2020
(3) SSC-CGL-MATHS-17-01-2020
(4) SSC-CGL-MATHS-17-01-2020

Q.4:- A right circular cylinder of maximum size is cut from the solid cube of edge 21 cm. Remaining part of cube is what percent of original cube?

एक ठोस 21 सेमी भुजा वाले घन से एक अधिकतम आकार का लम्बवृतीय बेलन काटा जात है तो घन का बचा हुआ भाग वास्तविक भाग का कितना प्रतिशत है ?

(1) 19.7%
(2) 23.2%
(3) 24.3%
(4) 21.4%

Q.5:-Find the value of SSC-CGL-MATHS-17-01-2020.

SSC-CGL-MATHS-17-01-2020का मान ज्ञात कीजिये।


(1) SSC-CGL-MATHS-17-01-2020    
(2) SSC-CGL-MATHS-17-01-2020
(3) SSC-CGL-MATHS-17-01-2020
(4) SSC-CGL-MATHS-17-01-2020

Q.6:- Find the number of zero in the following expression.
SSC-CGL-MATHS-17-01-2020

निम्नलिखित में शून्यों की संख्या ज्ञात कीजिये।
SSC-CGL-MATHS-17-01-2020

(1) 10
(2) 8
(3) 7
(4) 6

Q.7:- Find the value of following expression.
SSC-CGL-MATHS-17-01-2020

निम्नलिखित अभिव्यक्ति का मान ज्ञात कीजिये।
SSC-CGL-MATHS-17-01-2020

(1) SSC-CGL-MATHS-17-01-2020
(2) SSC-CGL-MATHS-17-01-2020
(3) SSC-CGL-MATHS-17-01-2020
(4) SSC-CGL-MATHS-17-01-2020

Q.8:- Find the quadratic equation having roots α and β such that
αβ = 14 and αβ= - 33

द्विघातीय समीकरण ज्ञात कीजिये जिसके मूल α तथा β इस प्रकार हैं कि
αβ = 14 and αβ= - 33 

(1) SSC-CGL-MATHS-17-01-2020
(2) SSC-CGL-MATHS-17-01-2020
(3) SSC-CGL-MATHS-17-01-2020   
(4) SSC-CGL-MATHS-17-01-2020

Q.9:- A container contains 80 liter milk and water and percentage of milk is 31.25%. How much more milk should be added so that milk and water becomes equal?

एक कंटेनर में 80 लीटर दूध और पानी है और दूध का प्रतिशत 31.25% है। कितना दूध और मिलाया जाए ताकि दूध और पानी की मात्रा बराबर हो जाए?

(1) 24 liter   /   लीटर
(2) 30 liter  /    लीटर
(3) 36 liter  /    लीटर
(4) 25 liter  /    लीटर

Q.10:- Find the angle between hour and minute hand of a clock at 11:22 hrs. (in degree)

11:22 बजे एक घड़ी के घंटे और मिनट सुई के बीच कोण ज्ञात कीजिये। (डिग्री में)

(1) 145
(2) 151
(3) 153
(4) 159










Answer:-

1. Sol:- (2)

LCM of 165 , 176 , 385, 495 = 55440 = K
HCF of 209, 418 , 539, 319 = 11
P = 55440/11 = 5040
12.5% of 5040 = 630

2. Sol:- (4) 

SSC-CGL-MATHS-17-01-2020
( 27 – 16 ) = 11 unit = 12650
1 unit = 1150 ,
100 unit = 115000 = X

3.Sol:- (3)

SSC-CGL-MATHS-17-01-2020
In Triangle BCD,
Tan45 = H/CD                                                         (tan45 = 1)
CD = H
Tan60 = (11 + H)/ CD
CD = SSC-CGL-MATHS-17-01-2020
H = SSC-CGL-MATHS-17-01-2020

4. Sol:- (4)

Volume of cube = SSC-CGL-MATHS-17-01-2020= 9261
Volume of cone = SSC-CGL-MATHS-17-01-2020
Remaining part = 9261 – 7276. 5 = 1984.5
Required percentage = SSC-CGL-MATHS-17-01-2020

5.Sol:- (1)

SSC-CGL-MATHS-17-01-2020

6.Sol:- (4) 

SSC-CGL-MATHS-17-01-2020

7.Sol:- (4)

SSC-CGL-MATHS-17-01-2020


8. Sol:- (3)

on solving α=11 and β=-3
SSC-CGL-MATHS-17-01-2020
हल करनें पर α=11 and β=-3
SSC-CGL-MATHS-17-01-2020

9.Sol:- (2)

             Milk     :      Water
Before     5      :        11
After      11     :       11
So for each 16 liter we need to add 6 milk
Here 16=80
So 6=30 liter

9.Sol:- (2)

             दूध     :      पानी
पहले   5      :        11
बाद      11     :       11
अतः प्रत्येक 16 लीटर के लिए हमें 6  दूध मिलानें की आवश्यकता है
यहाँ 16=80
अतः 6=30 लीटर

10.Sol:- (2)  

Required answer= SSC-CGL-MATHS-17-01-2020
अभीष्ट कीजिये= SSC-CGL-MATHS-17-01-2020

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