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SSC CHSL Quiz : Quantitative Aptitude | 03 - 06 - 19

Mahendra Guru
SSC CHSL Quiz : Quantitative Aptitude | 03 - 06 - 19
In SSC exam, quantitative Aptitude section is more scoring and easy, if you know the shorts tricks and formulas of all the topics. So, it is important to know the basic concepts of all the topics so you can apply the short tricks and solve the question with the new concepts in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz of quantitative Aptitude section helps you to analyse your preparation level for the upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exams like Insurance, SSC-MTS, SSC CPO, CGL, CHSL, State Level, and other Competitive exams.


So, here we will provide you a set of 10 questions of Quantitative Aptitude, important for SSC CHSL exam.

Ques. 1. If cos63o = x then find the value of tan27o.

यदि cos63o = x तो tan27o का मान ज्ञात कीजिये |
(A)
(B)
(C)
(D)

Ques. 2. If x = 8 + 2 then find the value of
यदि x = 8 + 2 तो का मान ज्ञात कीजिये ।
(A)
(B)
(C)
(D)

Ques. 3. A man can row a distance with the flow of stream at 12 km./hr. and he comes at the starting point against the rate of stream at 8 km./hr. What percent of the rate of stream is the rate of man in still water?

एक व्यक्ति धारा के प्रवाह के अनुकूल एक दूरी 12 किमी./घंटा की चाल से तैर सकता है और वह वापस प्रारम्भिक बिंदु पर धारा के प्रवाह के प्रतिकूल 8 किमी./घंटा की चाल से वापस आता है | व्यक्ति की स्थिर जल में चाल धारा के चाल का कितना प्रतिशत है ?
(A) 400%
(B) 500%
(C) 200%
(D) 450%

Ques. 4. The remainder, when 1739 + 2939 is divided by 23 is

1739 + 2939 को 23 से भाग देने पर शेषफल है 
(A) 17
(B) 1
(C) 0
(D) 29

Ques. 5. If 0 < θ < 900, tan θ = then find the value of .
यदि 0 < θ < 900, tan θ = हो तो का मान ज्ञात कीजिये ।
(A) 109
(B) 109/10
(C) 190/10
(D) 109/190

Ques. 6. If x2 + y2 + z2  = xy + yz + zx, (x ≠ 0) then the value of

यदि x2 + y2 + z2  = xy + yz + zx, (x ≠ 0) then the value of
(A) 0
(B) 1
(C) 1/2
(D) 3/2

Ques. 7. The value of is 

का मान है 
(A) 0
(B) 1
(C) 2
(D) 3

Ques. 8. If then the value of is

यदि तो का मान है 
(A)
(B)
(C)
(D)

Ques. 9. If then is

यदि तो है 
(A) 13/12
(B) 12/13
(C) 12/5
(D) 5/12

Ques. 10. AB and CD are two parallel chords of a circle lying on the opposite side of the centre and the distance between them is 17 cm. the length of AB and CD are 10 cm and 24 cm respectively. The radius of the circle?

AB और CD एक वृत्त की दो समांतर जीवा है जो केंद्र के विपरीत और है और उनके बीच के दूरी 17 सेमी है AB और CD की लम्बाई क्रमश: 10 सेमी और 24 सेमी है वृत्त की त्रिज्या है? 
(A) 13
(B) 15
(C) 18
(D) 9

Answer Key:
Q1. (A) cos63o = x
cos (90 – 27)o = x
sin27o = x
cos27o =
tan27o =

Q2. (B)
x – 2 = 6 + 2 = 2( +)

Q3. (B) Speed of the man in still water/व्यक्ति की स्थिर जल में चाल = 10 km/hr./(किमी./घंटा)
Speed of the stream/धारा की चाल = 2 km/hr./(किमी./घंटा)
Required/अभीष्ट % =

Q4. (C) When n is odd number, then/जब n एक विषम संख्या है, तो 
Hence/यहाँ, 1739 + 2939 is divided by 17+29 = 46 i.e. 23 too
so remainder will be 0/अतः शेषफल 0 होगा । 

Q5. (B) tan θ =
tan θ = 3
sec2 θ = 10 
sin2 θ =

Q6. (D)  x2 + y2 + z2 = xy + yz + zx
2x2 + 2y2 + 2z2 = 2xy + 2yz + 2zx
x2 + y2 + z2 + x2 + y2 + z2 2xy – 2yz – 2zx = 0
(x – y) 2 + (y – z) 2 + (z – x) 2 = 0
(x – y) 2 = 0, (y – z) 2 = 0, (z – x) 2 = 0

x = y, y = z, z = x
x = y = z
Now/अब, = = 3/2 

Q7. (B) =
=
= = 1

Q8. (C)
3a – 2 =
=

Q9. (C)
Dividing both sides by cosq/ cosq से दोनों ओर भाग करने पर
5 + 12tanq = 13 secq
On squaring both sides, we get/दोनों ओर वर्ग करने पर, हम प्राप्त करते हैं
25 + 144 tan2q + 120 tanq = 169 sec2
25 + 144 tan2q + 120 tanq = 169 (1 + tan2q )
25 tan2q – 120 tanq + 144 = 0
(5 tanq – 12)2 = 0
5 tanq – 12 = 0
tanq = 12/5

Q10. (A) AE = 5 cm/सेमी let/माना OF = x, CF = 12 cm/सेमी and/और OE = 17 – x
x2 + 122 = r2 ….. (I)
(17 – x)2 + 52 = r2 ….. (II)
From (I) and (II), we get/(I) और (II) से, हम प्राप्त करते हैं
x2 + 122 = (17 – x)2 + 52
34x = 170
x = 5
r2 = 52 + 122
= 25 + 144 = 169
r = 13

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