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Thursday, 5 July 2018

Quantitative Aptitude Questions For SBI Clerk : 05 - 07 - 18

Mahendra Guru : Online Videos For Govt. Exams
Quantitative Aptitude Questions For SBI Clerk : 05 - 07 - 18
Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concepts of all the topics so that you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.

Mahendra Guru provides you a Bank Quiz of Quantitative Aptitude on daily basis to help you in your preparation for Govt jobs. Mahendra Guru also provides you important notes and study material for all subject and test through its website, Mahendra Guru App and YouTube channel apart from it Speed Test Portal. Most of these preparation products are also available for purchase on my shop. You can also visit Mahendras.org to get more information about our endeavour for your success. You can also study in details through our E-Mahendras Facebook and Mahendra Guru YouTube channel.

Q.(1–3). What approximate value should come in place of the question mark (?) in the following questions?

निम्नलिखित प्रश्नों में प्रश्नवाचक चिन्ह (?) के स्थान पर लगभग मान क्या आयेगा? 
Q.1.
(1) 18
(2) 13
(3) 11
(4) 16
(5) 20

Q.2. 19.068 × 18.345 × ? = 11538.9337
(1) 30
(2) 40
(3) 45
(4) 50
(5) 35

Q.3.
(1) 50
(2) 55
(3) 45
(4) 60
(5) 35

Q.(4–5). In each question two equation I & II are given, on the basis of these you have to find out relation between p and q.

निम्नलिखित प्रश्नों में दो समीकरण I और II दिए गये हैं आपको दोनो समीकरण हल करना है और उत्तर दीजिए-

Q.4. (I) p2 + 7p + 12 = 0
        (II) q2 – 2q – 8 = 0
(1) p = q or relation cannot be established/या सम्बन्ध स्थापित नहीं किया जा सकता 
(2) p > q 
(3) q > p 
(4) p ≥ q 
(5) q ≥ p

Q.5. (I) p2 – 3p + 2 = 0
        (II) q2 – 7q = – 12
(1) p = q or relation cannot be established/या सम्बन्ध स्थापित नहीं किया जा सकता 
(2) p > q 
(3) q > p 
(4) p ≥ q 
(5) q ≥ p

Q.(6–10). In each of the following number series a wrong number is given. Find out the wrong number.

निम्नलिखित संख्या श्रृंखला में एक संख्या गलत है। गलत संख्या ज्ञात कीजिये। 

Q.6. 26 146 66 115 90 99
(1) 26
(2) 66
(3) 115
(4) 146
(5) 99

Q.7. 7 8 9 21 9.25 51.25
(1) 7
(2) 9
(3) 8
(4) 9.25
(5) 51.25

Q.8. 144 72 24 6 1.2 0.3
(1) 72
(2) 24
(3) 6
(4) 1.2
(5) 0.3

Q.9. 4 11 10 48 173 888
(1) 4
(2) 11
(3) 10
(4) 173
(5) 888

Q.10. – 10 – 9 – 10 – 4 52 385
(1) – 10
(2) – 9
(3) – 4
(4) 52
(5) 385

Answer key:
Q1. (2) (1 + 7 + 4) + = ?
12 + = ?
12 +

Q2. (5)
= 35

Q3. (3)
? = 45

Q4. (3) (I) p2 + 7p + 12 = 0  
                   p2 + 4p + 3p + 12 = 0
                   p (p + 4) + 3 (p + 4) = 0
                   p = – 4, – 3
            (II) q2 – 2q – 8 = 0
                   q2 – 4q + 2q – 8 = 0
                   q (q – 4) + 2(q – 4) =0
                   q = 4, – 2
                   q > p


Q5. (3) (I) p2 – 3p + 2 = 0
                  p2 – 2p – p + 2 = 0
                  p (p – 2) – 1 (p – 2) = 0
                  p = 2, 1
           (II) q2 – 7q + 12 = 0
                 q2 – 4q – 3q + 12 = 0
                 q (q – 4) – 3 (q – 4) = 0
                 q = 4, 3

Q6. (4)  26 + 112 = 147
             147 – 92 = 66
             66 + 72 = 115
             115 – 52 = 90
             90 + 32 = 99

Q7. (2) 7 × 1 + 1 = 8
8 ÷ 2 + 2 = 6
6 × 3 + 3 = 21
21 ÷ 4 + 4 = 9.25
9.25 × 5 + 5 = 51.25

8. (4)

9. (3) 4 × 1 + 7 = 11
11 × 2 – 11 = 11
11 × 3 + 15 = 48
48 × 4 – 19 = 173
173 × 5 + 23 = 888

10. (3) 10 × 1 + 13 = 9
             9 × 2 + 23 = 10
            
10 × 3 + 33 = 3
            
3 × 4 + 43 = 52
             52 × 5 + 53 = 385

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