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# Quantitative Aptitude Questions For SBI Clerk : 26 - 05 - 18

Mahendra Guru
Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concepts of all the topics so that you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.

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Q- (1-3) What value will come in place of question mark (?) in the number-series given below?

निम्नलिखित संख्या श्रृंखला में प्रश्नचिन्ह (?) के स्थान पर क्या मान आयेगा

Q-(1) 8 12 23 53 138 ?
1. 384
2. 382
3. 386
4. 387
5. None of these

Q-(2) 13 61 ? 349 733 1501
1. 157
2. 152
3. 153
4. 155
5. None of these

Q-(3) 4 9 15 27.5 ? 150.5
1. 56
2. 59
3. 60
4. 63
5. None of these

Q-(4) The length of a room floor exceeds its breadth by 25 m. The area of the floor remains unaltered when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is

कमरे की फर्श की लम्बाई फर्श की चौड़ाई से 25 मी. अधिक है। यदि फर्श की लम्बाई 10 मी. कम कर दी जाये और चौड़ाई 8 मी. बढ़ा दी जाये, तो फर्श का क्षेत्रफल अपरिवर्तित रहता है, फर्श का क्षेत्रफल है-
1. 5400 m.2
2. 5600 m.2
3. 4800 m.2
4. 5100 m.2
5. None of these

Q-(5) Two trains x and y starts from station A and B towards B and A respectively. After passing each other they take 4 hours 48 minutes and 3 hours 20 minutes to reach B and A respectively. If train x is moving at 60 km/hr. Then find the speed of train y?

दो रेलगाड़ियों x तथा y दो स्टेशनों A और B से एक दूसरे की तरफ चली। एक दूसरे को पार करने के बाद उन्हें B और A तक पहुँचने में क्रमशः 4 घण्टे 48 मिनट तथा 3 घण्टे 20 मिनट लगे। यदि रेलगाड़ी की गति 60 किमी./घण्टे हो तो रेलगाड़ी y की गति ज्ञात कीजिए
1. 64 kmph
2. 48 kmph
3. 72 kmph
4. 68 kmph
5. None of these

Q-(6) A committee of 5 members is to be formed out of 4 Lawyers, 3 Engineers and 2 Doctors. In how many ways a committee of 2 Lawyers, 2 Engineers and 1 Doctor can be formed ?

4 वकील, 3 इंजीनियर और 2 डॉक्टर में से 5 सदस्यों की एक समिति बनानी है । 2 वकील, 2 इंजीनियर और 1 डॉक्टर की समिति कितने तरीकों से बनाई जा सकती है ?
1. 25
2. 64
3. 9
4. 36
5. None of these

Q-(7) The ratio of largest angle and second largest angle is 3 : 2.The smallest angle is 20% of the sum of largest angle and second largest angle. What is the difference between largest angle and second largest angle?

एक त्रिभुज के सबसे बड़े और दूसरे सबसे बड़े कोण का अनुपात क्रमशः 3 : 2 है। सबसे छोटा कोण, सबसे बड़े और दूसरे सबसे बड़े कोण के योग का 20% है। सबसे बड़े और दूसरे सबसे बड़े कोण के बीच अन्तर क्या है?
1. 20o
2. 10o
3. 40o
4. 50o
5. None of these

Q-(8) What approximate value will come in place of question mark (?) in the following question?

निम्नलिखित प्रश्न में प्रश्नचिह्न (?) के स्थान पर लगभग क्या मान आयेगा ?

589586 ÷ 102.014 + 87974.64 ÷ 110.20 = ?
1. 7200
2. 8200
3. 8500
4. 7500
5. 6600

Q-(9) In each of the following questions, two equations are given. You have to solve them and give answer.

निम्नलिखित प्रश्न में दो समीकरण I और II दिये गये है दोनों समीकरण हल कीजिए और उत्तर दीजिए
I.
II.

1. If p > q
2. If p > q
3. If p < q
4. If p < q
5. If p = q or relationship can not be established

Q-(10) In each of the following questions, two equations are given. You have to solve them and give answer.

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और उत्तर दीजिए-
I. p2 + 16p + 63 = 0
II. q2 + 13q + 42 = 0
1. If p > q
2. If p > q
3. If p < q
4. If p < q
5. If p = q or relationship can not be established

Q1-3

Q2-1

× 2 + 35, × 2 + 35, × 2 + 35, × 2 + 35, × 2 + 35

Q3-2

× 0.5 + 7, × 1 + 6, × 1.5 + 5, × 2 + 4, × 2.5 + 3

Q4-4

Let the breadth of floor be b m.
Then, length of the floor be (b + 25)
Area = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
b2 + 8b + 15b + 120 = b2 + 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 m.2

माना फर्श की चौड़ाई b मी. है |
तो, फर्श की लम्बाई (b + 25) होगी |
क्षेत्रफल = (b + 25) × b
प्रश्नानुसार,
(b + 15) (b + 8) = (b + 25) × b
b2 + 8b + 15b + 120 = b2 + 25b
2b = 120
b = 60 मी.
l = b + 25 = 60 + 25 = 85 मी.
फर्श का क्षेत्रफल = 85 × 60 = 5100 मी.2

Q5-3

We know that,
s2 = 72 kmph

Q6-4

Required ways = 4C2× 3C2× 2C1  = 36

Q7-5
x + y + z = 1800    ------(I)
z = (x + y) × 20/100
x + y = 5z           ------(II)
Statement (I) and (II)
6z = 1800
z = 300
x : y = 3 : 2
x + y = 1500
x = 900
y = 600
Difference = 900 - 600 = 300

Q8-5

5780 + 800 = ?
? = 6580

Q9-1

I.
15 + 8p = 5p
15 = – 3p
p = – 5
II.

q = - 6
Hence, p > q

Q10-4
I. p2 +16p + 63 = 0
p2 + 9p + 7p + 63 = 0
p(p + 9) + 7(p + 9) = 0
(p + 9)(p + 7) = 0
p = –9, p = –7
II. q2 +13q + 42 = 0
q2 + 7q + 6q + 42 = 0
q(q + 7) + 6(q + 7) = 0
(q + 7)(q + 6) = 0
q = –7, q = –6
Hence, q > p