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Monday, 2 April 2018

Quantitative Aptitude Questions For SBI Clerk : 02 - 04 - 18

Mahendra Guru : Online Videos For Govt. Exams
Quantitative Aptitude Questions For SBI Clerk : 31 - 03 - 18

Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.
Mahendra Guru provides you a Bank Quiz of Quantitative Aptitude on daily basis to help you in your preparation for Govt job. You can clear your doubts before an exam. Mahendra Guru also provides you an important note and study material for all subject and test through its website, Mahendra Guru App and YouTube channel apart from it Speed Test Portal. Most of these preparation products are also available for purchase on my shop. You can also visit Mahendras.org to get more information about our endeavour for your success. You can also study in details through our E-Mahendras Facebook and Mahendra Guru YouTube channel 

Q-1      The simple interest on a certain amount at 12 p.c.p.a. in four years is Rs.6000. What will be compound interest on the same sum at the rate of interest 6 p.c.p.a. in 2 years?

किसी मूलधन पर 12 प्र.श.प्र.व. की दर से चार वर्ष में 6000 रू. का साधारण ब्याज उपचयित होता है। 2 वर्ष में 6 प्र.श.प्र.व. की दर से उसी मूलधन पर चक्रवृद्धि ब्याज कितना होगा?


(1) 1545 Rs./रु.

(2) 1628 Rs./रु.

(3) 1484 Rs./रु.

(4) 1590 Rs./रु.

(5) None of these/इनमें से कोई नहीं    
    
Q-2      Train x crosses a pole in 33 seconds and another train y crosses a pole in 44 seconds. The length of the train x is half of train y. What is the respective ratio between the speed of train x and y?

रेलगाड़ी x एक खम्भे को 33 सेकेण्ड में और दूसरी रेलगाड़ी y खम्भे को 44 सेकण्ड में पार करती है। रेलगाड़ी x की लम्बाई, रेलगाड़ी y की लम्बाई की आधी है तो रेलगाड़ी x और y की चालों के बीच क्रमशः अनुपात क्या है ?

(1) 7: 5

(2) 5: 4

(3) 2: 3

(4) 1: 2

(5) None of these/इनमें से कोई नहीं  
            
Q-3The average of four consecutive even numbers A, B, C and D is 37. What is the product of A and C?

A, B, C और क्रमशः चार क्रमागत सम संख्याओं का औसत 37 है। A और C का गुणनफल क्या है?

(1) 1480

(2)
1292

(3) 1520

(4)
1325

(5) None of these/इनमें से कोई नहीं                         
          
Q-4   The average age of 11 players of a cricket team is increased by 2 months when two of them aged 18 years and 20 years are replaced by two new players. The average age of the new players is-

किसी क्रिकेट टीम के 11 खिलाड़ियों की औसत आयु 2 माह बढ़ जाती है, जब टीम के दो खिलाड़ियों जिनकी आयु 18 वर्ष तथा 20 वर्ष है, जो दो अन्य खिलाड़ियों द्वारा प्रतिस्थापित किये जाते है। नये खिलाड़ियों की औसत आयु ज्ञात कीजिये|

(1) 18 years 7 months / 18 वर्ष 7 माह

(2)19 years 5 months / 19 वर्ष 5 माह

(3) 19 years 9 months / 19 वर्ष 9 माह 

(4)
19 years 11 months / 19 वर्ष 11 माह 

(5) None of these/इनमें से कोई नहीं        
      
Q-(5-7)   What value will come in place of question mark (?) in the questions given below ?

निम्नलिखित प्रश्नों में प्रश्नचिन्ह (?) के स्थान पर क्या मान आयेगा ?  
         
Q-5   (24.1)2 + (46.8)2 - (29.8)2 = ? + 1248.89

 (1) 629.32

(2) 642.62

(3) 634.12

(4) 651.82

(5) None of these/इनमें से कोई नहीं              
            
   Q-6     135% of 128 + 115% of 25  = ?

(1) 201.55

(2) 233.65

(3) 303.85

(4) 275.15

(5) None of these/इनमें से कोई नहीं                        

Q-7  ?% of 400 + 40% of 160 = 17% of 400

 (1) 7

(2) 2

(3) 5

(4) 3

(5) None of these/इनमें से कोई नहीं     
                  
Q-(8-10)    In each of the following questions, two equations are given. You have to solve them and give answer.

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और उत्तर दीजिए-

Q-(I)  3x + 5y = 29              (II)     4x – y = 8

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5)
If x=y or relationship cannot be established/ यदि x=y या सम्बन्ध स्थापित नहीं किया जा सकता है।

Q-9 (I)  x2 – 21 x + 68 = 0              (II)  y2 – 3y – 4 = 0

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5)
If x=y or relationship cannot be established/ यदि x=y या सम्बन्ध स्थापित नहीं किया जा सकता है।

Q-10 (I)    x = bank quiz 02-04-18

(II)  2y2 - 9y - 56 = 0

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5)
If x=y or relationship cannot be established/ यदि x=y या सम्बन्ध स्थापित नहीं किया जा सकता है।
  1. Sol-(1)
                bank quiz 02-04-18
  2. Sol-(3)
                bank quiz 02-04-18
  3. Sol-(2) Number = 34, 36, 37, 38, 40
                Product = 34 × 38
                = 1292
  4. Sol-(2) Total age of 2 players = 18+20 = 38 years
                increased years = 2×11 = 22 months
                38 years + 22 months = 39 years 10 months
                average = 19 years 11 months
दोनों खिलाड़ियों की कुल आयु - 18+20 = 38 वर्ष
वृद्धि वर्ष = 2×11 = 22 माह
38 वर्ष + 22 माह = 39 वर्ष 10 माह
औसत = 19 वर्ष 11 माह
    • Sol-(3) 580.81 + 2190. 24 - 888.04 = ? + 1248.89
                  ? = 1883.01 - 1248.89
                   = 634.12   
    • Sol-(1) ? = 172.8 + 28.75=201.55
    • Sol-(5) 4 × ? = 68 - 64 = 4
                  ? = 1 
    • Sol-(3) 3x + 5y = 29 × 1
                  4x – y = 8×5
                  3x + 5y = 29
                  20x – 5y = 40
                  23x = 69
                  x = 3
                  y = 4
                 Q.1.                      x < y
      Sol-(2) (I)  x2 – 17x – 4x + 68 = 0    (II)     y2– 4y + y – 4=0

    •             x(x – 17)  – 4 (x – 17)=0           y(y – 4) + 1(y – 4)=0
                  (x – 17) (x – 4) = 0                    (y – 4) (y + 1) = 0
                  x= +17, +4                                y = + 4, – 1
                  Hence, x> y
    • Sol-(1) (I)  x = 9
                  (II)  2y2 - 16y + 7y -56 = 0
                  2y (y-8) + 7 (y-8) = 0
                  y = 8, - 7/2
                  x > y         

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