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Monday, 30 April 2018

Quantitative Aptitude Questions For SBI Clerk : 30 - 04 - 18

Mahendra Guru : Online Videos For Govt. Exams
Quantitative Aptitude Questions For SBI Clerk : 30 - 04 - 18
Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concepts of all the topics so that you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.

Mahendra Guru provides you a Bank Quiz of Quantitative Aptitude on daily basis to help you in your preparation for Govt jobs. Mahendra Guru also provides you important notes and study material for all subject and test through its website, Mahendra Guru App and YouTube channel apart from it Speed Test Portal. Most of these preparation products are also available for purchase on my shop. You can also visit Mahendras.org to get more information about our endeavour for your success. You can also study in details through our E-Mahendras Facebook and Mahendra Guru YouTube channel.

Q. (1–3): What will come at the place of question mark (?) in the following questions?

निम्नलिखित प्रश्नों में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आयेगा ?

Q1. (35426 + 7164 + 41720) – (317 × 89) = ?
(1) 28213
(2) 84307
(3) 50694
(4) 54096
(5) इनमें से कोई नहीं

Q2. (9% of 386) × (6.5% of 144) = ?
(386 का 9%) × (144 का 6.5%) = ?
(1) 340.1664
(2) 325.1664
(3) 333.3333
(4) 328.0065
(5) इनमें से कोई नहीं

Q3.
(1) 884751
(2) 804051
(3) 854749
(4) 814751
(5) इनमें से कोई नहीं

Q4. Om invested Rs.15000 on compound interest at the rate of 9% interest per annum and Rs.12000 on compound interest at the rate of 8% of the annual interest rate. After two years, how much interest will be available in the form of interest?

ओम ने रु.15000 को 9 प्रतिशत वार्षिक ब्याज की दर से साधारण ब्याज पर और रु.12000 को 8 प्रतिशत वार्षिक ब्याज की दर से चक्रवृद्धि ब्याज पर निवेश किया | दो वर्ष के बाद कुल कितनी ब्याज के रूप में राशि प्राप्त होगी?
(1) Rs.4966.8
(2) Rs.4666.8
(3) Rs.4686.8
(4) Rs.4696.8
(5) Rs.4669.8

Q5. The sum of two odd numbers is 38 and their product is 325. What will be the treble of the large number?

दो विषम संख्याओं का योगफल 38 है एवं उनका गुणनफल 325 है | बड़ी संख्या का तिगुना क्या होगा?
(1) 42
(2) 39
(3) 75
(4) 72
(5) 78

Q6. The ratio of the current age Anil and Sakshi is 21: 19, respectively. The ratio of their ages six years ago was 9: 8, respectively. What is the current age of Tanishka, if her current age is 12 years less than from the current age of Sakshi?

अनिल और साक्षी की वर्तमान आयु में अनुपात क्रमशः 21: 19 है | छह वर्ष पूर्व उनकी आयु का अनुपात क्रमशः 9: 8 था | तनिष्का की वर्तमान आयु क्या है यदि उसकी वर्तमान आयु साक्षी की वर्तमान आयु से 12 वर्ष कम है?
(1) 38 वर्ष 
(2) 28 वर्ष
(3) 26 वर्ष
(4) 30 वर्ष
(5) 42 वर्ष

Q7. Amit bought an item for Rs.7500. In the purchase of it, he spent (7.8125) th part of cost price of the article. Then he sold it at Rs.12267. How much profit did he get in this transaction?

अमित ने एक वस्तु 7500 रु. में खरीदी | इसकी खरीदारी में उसने क्रय मूल्य का (7.8125) भाग खर्च किया| उसने फिर इसे 12267 रु. में बेच दिया | इस लेन – देन में उसे कितना प्रतिशत लाभ हुआ ?
(1) 38
(2) 45
(3) 46
(4) 35
(5) 48

Q.(8–10): In each of the questions given below, two equations (I) and (II) are given. You have to solve both and answer

नीचे दिए गए प्रत्येक प्रश्न में दो समीकरण (I) और (II) दिए गए हैं | आपको दोनों को हल करना है और उत्तर देना है 
(1) If/यदि p < q
(2) If/यदि p > q
(3) If/यदि p > q
(4) If/यदि p < q
(5) If p = q or no relation cannot be established between p and q.
यदि p = q या p और q में कोई सम्बन्ध स्थापित नहीं किया जा सकता है |

Q8. I. 6p2 + 5p + 1 = 0
    II. 15q2 + 8q + 1 = 0

Q9. I. 88p2 – 19p + 1 = 0
    II. 132q2 – 23q + 1 = 0

Q10. I. 6p2 – 7p + 2 = 0
      II. 20q2 – 31q + 12 = 0

ANSWER KEY:

Q1. (5) (84310) – (28213) = ?
? = 56097

Q2. (2) 34.74 × 9.36 = ?
? = 325.1664
Q3.  (1)
(96)3 = ? – 15
884736 + 15 = ?
884751 = ?
Q4.  (4) Total interest/कुल ब्याज =
= 2700 + 1996.8
= Rs.4696.8

Q5. (3) a + b = 38 … (I)
ab = 325 … (II)
On solving (I) and (II), we get/(I) और (II) को हल करने पर, हम प्राप्त करते हैं 
a = 13 and b = 25
Treble of larger number/बड़ी संख्या का तिगुना = 25 × 3 = 75

Q6. (4) According to the question/प्रश्नानुसार,
168x – 48 = 171x – 54 
3x = 6
x = 2
Sakshi's present age/साक्षी की वर्तमान आयु = 21 × 2 = 42 years/वर्ष
Tanishka's present age/तनिष्का की वर्तमान आयु = 42 – 12 = 30 years/वर्ष 

Q7. (2) Total cost price for Amit/अमित के लिए कुल क्रय मूल्य = Rs.7500 + (7500 ÷ 7.8125) 
= Rs.7500 + Rs.960 = Rs.8460
Selling price/विक्रय मूल्य = Rs.12267
Profit/लाभ % = = 45%

Q8. (4) I. 6p2 + 5p + 1 = 0
               6p2 + 3p + 2p + 1 = 0
               2p (3p + 1) + 1 (2p + 1) = 0
               (2p + 1) (3p + 1) = 0
               p = - 1/2, - 1/3
           II. 15q2 + 8q + 1 = 0
                15q2 + 3q + 5q + 1 = 0
               3q (5q + 1) + 1 (5q + 1) = 0
               (3q + 1) (5q + 1) = 0
                q = - 1/3, - 1/5
               Hence/अतः, p < q

Q9. (4)I. 88p2 – 19p + 1 = 0
               88p2 – 11p – 8p + 1 = 0
               11p (8p – 1) – 1 (8p – 1) = 0
               (11p – 1) (8p – 1) = 0
               p = 1/11, 1/8
            II. 132q2 – 23q + 1 = 0
                132q2 – 12q – 11q + 1 = 0
                12q (11q – 1) – 11 (11q – 1) = 0
                (11q – 1) (12q – 11) = 0
                 q = 1/11, 11/12
                Hence/अतः, p < q

Q10. (1) 
     I. 6p2 – 7p + 2 = 0
         6p2 – 4p – 3p + 2 = 0
         2p (3p – 2) – 1 (3p – 2) = 0
         (2p – 1) (3p – 2) = 0
          p = 1/2, 2/3
     II. 20q2 – 31q + 12 = 0
          20q2 – 16q – 15q + 12 = 0
          4q (5q – 4) – 3 (5q – 4) = 0
          (5q – 4) (4q – 3) = 0
          q = 4/5, 3/4
        Hence/अतः, p < q

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