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# Quantitative Aptitude Questions For SBI Clerk : 31 - 03 - 18

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Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.

Q-(1–3) What approximate value will come in place of the question mark (?) in the following questions?
निम्नलिखित प्रश्नों में प्रश्नचिन्ह (?) के स्थान पर लगभग क्या मान आयेगा?

Q- 1     323.11 + 729.82 + 11.01 + 15.542 = ?

(1) 1120
(2) 1080
(3) 960
(4) 840
(5) 1210

Q-2      43.99% of 550.28 + 25.12% of 131 =?

550.28 का 43.99% + 131 का 25.12% = ?

(1) 300
(2) 200
(3) 250
(4) 225
(5) 275

Q-3      (29.88)2 + (11.21)2 - (9.11)3 = ?

(1) 340
(2) 290
(3) 180
(4) 220
(5) 375

Q-4      44.98 × 2.12 + 231.112 = ?

(1) 320
(2) 225
(3) 260
(4) 9600
(5) 365

Q-(5–6) In each of the following questions, two equations (I) and (II) are given. You have to solve them and state the correct relationship,

निम्नलिखित प्रश्नों में दो समीकरण I और II दिए गए हैं। इन दोनों को हल कीजिये एवं सही सम्बन्ध स्थापित कीजिये।

Q-5   (I) 4x2 + 27x + 38 = 0     (II) y2 – 3y – 40 = 0

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship can not be established/x = y या सही सम्बन्ध स्थापित नहीं किया जा सकता है।

Q-6   (I) x3 – 15x = (20 – x) × 15 + 212              (II) 2y– 13y + 15 = 0

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x=y or relationship can not be established/x=y या सही सम्बन्ध स्थापित नहीं किया जा सकता है।

Q-(7–10) Read the following graph carefully and answer the questions given below.
Ratio of export and import of two companies in different years (amount in Rs.)

निम्नलिखित ग्राफ का ध्यानपूर्वक अध्ययनकर नीचे पूछे गये प्रश्नों के उत्तर दीजिये।

Q-7 In which year/years, the difference between import and export of company B was maximum? किस वर्ष/वर्षों में कंपनी B के आयात और निर्यात में अंतर अधिकतम था ?

(1) 2012
(2) 2008
(3) 2010 and 2012/210 तथा 2012
(4) Data inadequate/ आँकड़े अधूरे हैं
(5) None of these/इनमें से कोई नहीं

Q-8 The export of company A was twice that of company B in the year 2008. If import of company A was Rs.400 crore in that year, what was approximate import of company B in that year?

वर्ष 2008 में कंपनी A का निर्यात कंपनी B से दोगुना था। यदि कंपनी A का आयात उस वर्ष रू. 400 करोड़ था तो उस वर्ष कंपनी B का आयात लगभग कितना था?

(1) 420 crore/करोड़
(2) 380 crore/करोड़
(3) 470 crore/करोड़
(4) 519 crore/करोड़
(5) None of these/इनमें से कोई नहीं

Q-9 In how many year/years, the export is more than import for company A?

कितने वर्ष/वर्षों में कंपनी A का निर्यात आयात से अधिक है ?

(1) All years / सभी वर्षो में
(2) 4
(3) 2
(4) 1
(5) None of these/इनमें से कोई नहीं

Q-10 The export of company B in 2011 was Rs.350 crore. What is the import of that company in 2012?

यदि 2011 में कंपनी B का निर्यात रू.350 करोड़ है तो 2012 में उसी कंपनी का आयात कितना है?

(1) Data inadequate/ आँकड़े अधूरे हैं
(2) 350
(3) 425
(4) 275
(5) None of these/इनमें से कोई नहीं

Q.1  (2)
? = 323 + 730 + 11 + 15
= 1080 (approx./लगभग)

Q.2  (5)
? = 242 + 33= 275 (approx./लगभग)

Q.3  (2)
? = 900 + 121 - 730
= 290 (approx./लगभग)

Q.4  (1)
? = 90 + 230
= 320 (approx./लगभग)

Q.5 (5)
(I)   4x2 + 19x + 8x + 38 = 0                                                             (II) y2 – 8y + 5y – 40= 0
x (4x + 19) + 2(4x +19) = 0                                        y(y – 8)+5 (y – 8) = 0
(4x + 19) (x + 2) = 0                                                   (y – 8) (y + 5) = 0
x = -19/4, -2                                                               y = +8, – 5
Relation can’t be established/
सम्बन्ध ज्ञात नहीं किया जा सकता

Q.6 (1)

(I)  x3 – 15x = 300 - 15x +212                              (II)   2y2 – 10y – 3y +15 = 0
x3 = 512                                                           2y(y – 5) – 3(y – 5) = 0
x = 8                                                                 (y – 5) (2y - 3) = 0
y = 5, 3/2

Q.7 (4)