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# SSC Quiz : Quantitative Aptitude | 05 - 02 - 18

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In SSC exam quantitative Aptitude section is more scoring and easy if you know the shorts tricks and formulas of all the topic. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with the new concept in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz Of quantitative Aptitude section helps you to analysis your preparation level for upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like Insurance, SSC-MTS, CGL, CHSL, State Level, and other Competitive exams.

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Q1.If n is a positive integer, then what is the digit in the unit place of 32n+1+2n+1?

यदि n एक धनात्मक पूर्णांक है, तो 32n+1+2n+1 का इकाई का अंक क्या है?
1. 0
2. 3
3. 5
4. 7
SOL :

By Hit and trial - 5

Q2 . What is the last digit in the expansion  of 34798?

34798 के विस्तार में अंतिम अंक क्या है?
1. 1
2. 3
3. 7
4. 9
SOL :

34798 = (34)1199.32 = 9

Q.3 What are the factor of x2+4y2+4y-4xy-2x-8

x2+4y2+4y-4xy-2x-8 के गुणनखण्ड क्या है?
1. (x-2y-4) and (x-2y+2)
2. (x-y+2) and (x-4y+4)
3. (x-y+2) and (x-4y-4)
4. (x+2y-4) and (x+2y+2)

SOL :

x2+4y2+4y-4xy-2x-8
= (x-2y)2-2(x-2y)-8
= (x-2y)2-4(x-2y)+2(x-2y)-8 = (x-2y-4)(x-2y+2)

Q4.  What is the sum of the digits of the least number which, when divided by 52, leaves 33 as a remainder, when divided by 78, leaves 59 and when divided by 117, leaves 98 as remainder?

उस न्यूनतम संख्या के अंको का योग क्या है, जिसे 52, से विभाजित करने पर 33 शेष रहता है, 78 से विभाजित करने पर 59 शेष रहता है और 117 से विभाजित करने पर 98 शेष रहता है?

1. 17
2. 18
3. 19
4. 21
SOL :

52-33 = 78-59 = 117-98 = 19
LCM of 52, 78, 117 = 468
number = 468-19 = 449
Required Sum = 4 + 4+ 9 = 17

Q5.) The number of males per hundred females in a country was 120.At the next census, the total population increased by 5% and the female population increased by 10%.Find the percent in the male population

एक देश में प्रति सौ महिलाओं पर 120 पुरूष थे। अगली जनगणना में 5% की वृद्धि हुयी और महिला जनसंख्या में 10% की वृद्धि हुयी। पुरूष जनसंख्या में हुयी प्रतिशत वृद्धि ज्ञात कीजिए?

1. 0.833%
2. 1.333%
3. 1%
4. 3%
SOL :

0.833%

Q6.) The ratio between the ages of A and B is 2 : 5.After 8 years, their ages will be in the ratio 1: 2.What is the difference between their present ages?
A और B की उम्र के बीच का अनुपात 2 : 5 है। 8 वर्ष पश्चात् उनकी उम्रों का अनुपात 1: 2 होगा। वर्तमान में उनकी उम्रों का अन्तर क्या है?

1. 20
2. 22
3. 24
4. 25
SOL :

Let the age of A and B be 2x and 5x
According to the question
4x+16 = 5x+8
x = 8
Required difference = 2×8 5×8 = 24 year

Q7.)  A person can do a job as fast as his two sons working together. If one son does the job in 6 days and other in 12 days. How many days does it take the father to do the job?

एक व्यक्ति एक काम को इतनी तेज कर सकता है जितना कि उसके दो पुत्र एक साथ मिलकर कर सकते है। यदि एक पुत्र काम को 6 में और दूसरा 12 दिनों में करता है तो पिता को काम करने में कितने दिन लगेंगे?
1. 2
2. 4
3. 3
4. 5
Sol :

Q8.)The wages of laborers in a factory has increased in the ratio 22:25 and their number decreased in the ratio 3:2.What was the original wage bill of the factory if the percent is Rs 5000?

एक फैक्ट्ररी में श्रमिकों की मजदूरी में 22:25 की वृद्धि कर दी जाती है, और उनकी संख्या में 3:2 की कमी कर दी जाती है। वास्तविक मजदूरी बिल क्या था, यदि वर्तमान बिल 5000 रू. है?

1. Rs 4000
2. Rs 6000
3. Rs 6600
4. Rs 4600
Sol :

Let initial wages be 22x
final wages = 25x
Let initial number of laborers be 3y
Final number of laborers = 2y
Present bill = Final wages × final number of laborer
5000 = 25x×2y
Original bill = Initial wages × Initial number of labourers
= 22x × 3y = 66xy = 66×100 = 6600

Q9.) If x cos600 + y cos00 = 3 and 4x sin300 - ycot 450 = 2 then what is the value of x?

यदि x cos600 + y cos00 = 3 और 4x sin300 - ycot 450 = 2 तो x का मान क्या है?

1. – 1
2. 0
3. 1
4. 2
Sol :

Q10.)   D is any point an side AC of ΔABC.If P,Q, X, Y are the mid point of AB, BC, AD and DC respectively, then the ratio of PX and QY is –

ΔABC की भुजा AC पर D कोई बिन्दु है। यदि P,Q, X, Y क्रमशः AB, BC, AD और DC का मध्य बिन्दु है तो PX और QY का अनुपात क्या है –

1. 1 : 2
2. 1 : 1
3. 2 : 1
4. 2 : 3
Sol :

Q.1 (C)

Q.2 (D)

Q.3 (A)

Q.4 (A)

Q.5 (A)

Q.6 (C)

Q.7 (B)

Q.8 (C)

Q.9 (D)

Q.10 (B)