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# Quantitative Aptitude Questions For IBPS Clerk Mains : 12 - 01 - 18

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Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.

Q.1 What value will come in place of question mark (?) in the number-series given below?

рдиिрдо्рдирд▓िрдЦिрдд рд╕ंрдЦ्рдпा рд╢्рд░ृंрдЦрд▓ा рдоें рдк्рд░рд╢्рдирдЪिрди्рд╣ (?) рдХे рд╕्рдеाрди рдкрд░ рдХ्рдпा рдоाрди рдЖрдпेрдЧा
8 12 23 53 138 ?

1. 384
2. 382
3. 386
4. 387
5. None of these

Solutions 3

Q.2 What value will come in place of question mark (?) in the number-series given below?

рдиिрдо्рдирд▓िрдЦिрдд рд╕ंрдЦ्рдпा рд╢्рд░ृंрдЦрд▓ा рдоें рдк्рд░рд╢्рдирдЪिрди्рд╣ (?) рдХे рд╕्рдеाрди рдкрд░ рдХ्рдпा рдоाрди рдЖрдпेрдЧा
13 61 ? 349 733 1501
1. 157
2. 152
3. 153
4. 155
5. None of these

Solutions 1
× 2 + 35, × 2 + 35, × 2 + 35, × 2 + 35, × 2 + 35

Q.3 What value will come in place of question mark (?) in the number-series given below?

рдиिрдо्рдирд▓िрдЦिрдд рд╕ंрдЦ्рдпा рд╢्рд░ृंрдЦрд▓ा рдоें рдк्рд░рд╢्рдирдЪिрди्рд╣ (?) рдХे рд╕्рдеाрди рдкрд░ рдХ्рдпा рдоाрди рдЖрдпेрдЧा
4 9 15 27.5 ? 150.5

1. 56
2. 59
3. 60
4. 63
5. None of these

Solutions 2

× 0.5 + 7, × 1 + 6, × 1.5 + 5, × 2 + 4, × 2.5 + 3

Q.4 The length of a room floor exceeds its breadth by 25 m. The area of the floor remains unaltered when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is

рдХрдорд░े рдХी рдлрд░्рд╢ рдХी рд▓рдо्рдмाрдИ рдлрд░्рд╢ рдХी рдЪौреЬाрдИ рд╕े 25 рдоी. рдЕрдзिрдХ рд╣ै। рдпрджि рдлрд░्рд╢ рдХी рд▓рдо्рдмाрдИ 10 рдоी. рдХрдо рдХрд░ рджी рдЬाрдпे рдФрд░ рдЪौреЬाрдИ 8 рдоी. рдмреЭा рджी рдЬाрдпे, рддो рдлрд░्рд╢ рдХा рдХ्рд╖ेрдд्рд░рдлрд▓ рдЕрдкрд░िрд╡рд░्рддिрдд рд░рд╣рддा рд╣ै, рдлрд░्рд╢ рдХा рдХ्рд╖ेрдд्рд░рдлрд▓ рд╣ै-

1. 5400 m.2
2. 5600 m.2
3. 4800 m.2
4. 5100 m.2
5. None of these

Solutions 4
Let the breadth of floor be b m.
Then, length of the floor be (b + 25)
Area = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
b2 + 8b + 15b + 120 = b2 + 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 m.2

рдоाрдиा рдлрд░्рд╢ рдХी рдЪौреЬाрдИ b рдоी. рд╣ै |
рддो, рдлрд░्рд╢ рдХी рд▓рдо्рдмाрдИ (b + 25) рд╣ोрдЧी |
рдХ्рд╖ेрдд्рд░рдлрд▓ = (b + 25) × b
рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
(b + 15) (b + 8) = (b + 25) × b
b2 + 8b + 15b + 120 = b2 + 25b
2b = 120
b = 60 рдоी.
l = b + 25 = 60 + 25 = 85 рдоी.
рдлрд░्рд╢ рдХा рдХ्рд╖ेрдд्рд░рдлрд▓ = 85 × 60 = 5100 рдоी.2

Q.5 Two trains x and y starts from station A and B towards B and A respectively. After passing each other they take 4 hours 48 minutes and 3 hours 20 minutes to reach B and A respectively. If train x is moving at 60 km/hr. Then find the speed of train y?

рджो рд░ेрд▓рдЧाреЬिрдпों x рддрдеा y рджो рд╕्рдЯेрд╢рдиों A рдФрд░ B рд╕े рдПрдХ рджूрд╕рд░े рдХी рддрд░рдл рдЪрд▓ी। рдПрдХ рджूрд╕рд░े рдХो рдкाрд░ рдХрд░рдиे рдХे рдмाрдж рдЙрди्рд╣ें B рдФрд░ A рддрдХ рдкрд╣ुँрдЪрдиे рдоें рдХ्рд░рдорд╢ः 4 рдШрдг्рдЯे 48 рдоिрдирдЯ рддрдеा 3 рдШрдг्рдЯे 20 рдоिрдирдЯ рд▓рдЧे। рдпрджि рд░ेрд▓рдЧाреЬी рдХी рдЧрддि 60 рдХिрдоी./рдШрдг्рдЯे рд╣ो рддो рд░ेрд▓рдЧाреЬी y рдХी рдЧрддि рдЬ्рдЮाрдд рдХीрдЬिрдП
1. 64 kmph
2. 48 kmph
3. 72 kmph
4. 68 kmph
5. None of these

Solutions 3

We know that,
s2 = 72 kmph

Q.6 A committee of 5 members is to be formed out of 4 Lawyers, 3 Engineers and 2 Doctors. In how many ways a committee of 2 Lawyers, 2 Engineers and 1 Doctor can be formed ?

4 рд╡рдХीрд▓, 3 рдЗंрдЬीрдиिрдпрд░ рдФрд░ 2 рдбॉрдХ्рдЯрд░ рдоें рд╕े 5 рд╕рджрд╕्рдпों рдХी рдПрдХ рд╕рдоिрддि рдмрдиाрдиी рд╣ै । 2 рд╡рдХीрд▓, 2 рдЗंрдЬीрдиिрдпрд░ рдФрд░ 1 рдбॉрдХ्рдЯрд░ рдХी рд╕рдоिрддि рдХिрддрдиे рддрд░ीрдХों рд╕े рдмрдиाрдИ рдЬा рд╕рдХрддी рд╣ै ?

1. 25
2. 64
3. 36
4. None of these

Solutions 4
Required ways = 4C2× 3C2× 2C1 = 36

Q.7. The ratio of largest angle and second largest angle is 3 : 2.The smallest angle is 20% of the sum of largest angle and second largest angle. What is the difference between largest angle and second largest angle?

рдПрдХ рдд्рд░िрднुрдЬ рдХे рд╕рдмрд╕े рдмреЬे рдФрд░ рджूрд╕рд░े рд╕рдмрд╕े рдмреЬे рдХोрдг рдХा рдЕрдиुрдкाрдд рдХ्рд░рдорд╢ः 3 : 2 рд╣ै। рд╕рдмрд╕े рдЫोрдЯा рдХोрдг, рд╕рдмрд╕े рдмреЬे рдФрд░ рджूрд╕рд░े рд╕рдмрд╕े рдмреЬे рдХोрдг рдХे рдпोрдЧ рдХा 20% рд╣ै। рд╕рдмрд╕े рдмреЬे рдФрд░ рджूрд╕рд░े рд╕рдмрд╕े рдмреЬे рдХोрдг рдХे рдмीрдЪ рдЕрди्рддрд░ рдХ्рдпा рд╣ै?

1. 20o
2. 10o
3. 40o
4. 50o
5. None of these

Solutions 5
x + y + z = 1800    ------(I)
z = (x + y) × 20/100
x + y = 5z           ------(II)
Statement (I) and (II)
6z = 1800
z = 300
x : y = 3 : 2
x + y = 1500
x = 900
y = 600
Difference = 900 - 600 = 300

Q.8. What approximate value will come in place of question mark (?) in the following question?

рдиिрдо्рдирд▓िрдЦिрдд рдк्рд░рд╢्рди рдоें рдк्рд░рд╢्рдирдЪिрд╣्рди (?) рдХे рд╕्рдеाрди рдкрд░ рд▓рдЧрднрдЧ рдХ्рдпा рдоाрди рдЖрдпेрдЧा ?

589586 ÷ 102.014 + 87974.64 ÷ 110.20 = ?

1. 7200
2. 8200
3. 8500
4. 7500
5. 6600

Solutions 5

5780 + 800 = ?
? = 6580

Q.9. In each of the following questions, two equations are given. You have to solve them and give answer.

рдиिрдо्рдирд▓िрдЦिрдд рдк्рд░рд╢्рди рдоें рджो рд╕рдоीрдХрд░рдг I рдФрд░ II рджिрдпे рдЧрдпे рд╣ै рджोрдиों рд╕рдоीрдХрд░рдг рд╣рд▓ рдХीрдЬिрдП рдФрд░ рдЙрдд्рддрд░ рджीрдЬिрдП
I.
II.

1. If p > q
2. If p > q
3. If p < q
4. If p < q
5. If p = q or relationship can not be established

Solutions 1

I.
15 + 8p = 5p
15 = – 3p
p = – 5
II.

q = - 6

Hence, p > q

Q.10. In each of the following questions, two equations are given. You have to solve them and give answer.

рдиिрдо्рдирд▓िрдЦिрдд рдк्рд░рд╢्рдиों рдоें рджो рд╕рдоीрдХрд░рдг (I) рдФрд░ (II) рджिрдпे рдЧрдпे рд╣ै рджोрдиों рд╕рдоीрдХрд░рдг рд╣рд▓ рдХीрдЬिрдП рдФрд░ рдЙрдд्рддрд░ рджीрдЬिрдП-

I. p2 + 16p + 63 = 0
II. q2 + 13q + 42 = 0

1. If p > q
2. If p > q
3. If p < q
4. If p < q
5. If p = q or relationship can not be established

Solutions 4

I. p2 +16p + 63 = 0
p2 + 9p + 7p + 63 = 0
p(p + 9) + 7(p + 9) = 0
(p + 9)(p + 7) = 0
p = –9, p = –7
II. q2 +13q + 42 = 0
q2 + 7q + 6q + 42 = 0
q(q + 7) + 6(q + 7) = 0
(q + 7)(q + 6) = 0
q = –7, q = –6
Hence, q > p