Dear Readers,
Mahendras has started special quizzes for SBI / RBI Main Exam so that you can practice more and more to crack the examination. This SBI / RBI Main Exam quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination. Here we are providing you important question of Quantitative aptitude for SBI / RBI Main Exam.
(1) L is as much younger than M as he is older than. If the sum of the ages of M and N is 60 years, what is the definitely the difference between M and L’s age?
(1) L is as much younger than M as he is older than. If the sum of the ages of M and N is 60 years, what is the definitely the difference between M and L’s age?
L, M से जितना छोटा है, वह उससे कहीं अधिक उम्र का है। यदि M और N की आयु का योग 60 वर्ष है, तो निश्चित रूप से M और L की आयु में क्या अंतर है?
(1) 3
(2) 2
(3) 5
(4) Can’t be determined/ निर्धारित नही किया जा सकता
(5) None of these/ इनमे से कोई नही
(2) A card from a pack of 52 cards is lost. From the remaining cards of the pack, two cards are drawn and are found to be both hearts. Find the probability of the lost card being a heart?
52 कार्ड के एक पैकेट से एक कार्ड खो जाता है। पैक के शेष कार्डों से, दो कार्ड खींचे जाते हैं और दोनों दिलों के लिए पाए जाते हैं। खोए हुए कार्ड की संभावना एक दिल होने का पता लगाएं?
(1) 12/50
(2) 8/50
(3) 11/50
(4) 9/50
(5) None of these/इनमे से कोई नही
(3) The average expenditure of Sharma for the January to June is Rs 4200 and he spent Rs 1200 in January and Rs 1500 in July. The average expenditure for the months of February to July is:
जनवरी से जून के लिए शर्मा का औसत खर्च 4200 रुपये है और उन्होंने जनवरी में 1200 रुपये और जुलाई में 1500 रुपये खर्च किए। फरवरी से जुलाई के महीनों के लिए औसत व्यय है:
(1) 2750
(2) 3250
(3) 4250
(4) 4500
(5) 3500
(4) A boat takes 26 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the velocity of the stream is 4 km/hr and the speed of the boat in still water is 10 km/hr, what is the distance between A and B?
एक नाव बिंदु A से बिंदु B तक यात्रा करने में 26 घंटे का समय लेती है और A और B के बीच बिंदु C के मध्य में वापस आती है। यदि धारा का वेग 4 किमी / घंटा है और स्थिर पानी में नाव की गति 10 किमी / घंटा है घंटा, A और B के बीच की दूरी क्या है?
(1) 210
(2) 185
(3) 140
(4) 168
(5) None of these/ इनमे से कोई नही
(5) A person wants to make a cylindrical box which is open from the top. If the height of that box is 10cm and radius is 7 cm find the area of sheet which is required to make it.
एक व्यक्ति एक बेलनाकार बॉक्स बनाना चाहता है जो ऊपर से खुला हो। यदि उस बॉक्स की ऊंचाई 10 सेमी है और त्रिज्या 7 सेमी है तो शीट का क्षेत्रफल ज्ञात करें जिसे इसे बनाने के लिए आवश्यक है।
(1) 880
(2) 1188
(3) 594
(4) 440
(5) None of these/इनमे से कोई नही
Q-(6-10) What approximate value will come at place of question mark (?) in the following questions?
निम्नलिखित प्रश्नों में प्रश्न चिह्न (?) के स्थान पर लगभग क्या मान आएगा?
(6) 129% of 649 – 24.872=?
(1) 200
(2) 180
(3) 220
(4) 240
(5) 260
(7) 212×89–32×55=?3
(1) 21
(2) 23
(3) 26
(4) 18
(5) 29
(8) 143.88% of 384 = ?%
of 149 + 10.962
(
1) 250
(2) 270
(3) 290
(4) 320
(5) 220
(9) 87.222+61.792=?% of 899 + 41.882
1) 250
(2) 270
(3) 290
(4) 320
(5) 220
(9) 87.222+61.792=?% of 899 + 41.882
(1) 1070
(2) 1040
(3) 1010
(4) 970
(5) 940
(10) 233–562=?%
of 695
(1)
1230
(2)
1290
(3)
1260
(4)
1140
(5)
1170
Answer Key-
Q-(1) Sol-(4)
M – L = L – N
( M+N) = 2L
Given (M+N) = 60
then 2L = 60
L = 30
But can’t be able to find M value
therefore, can’t be determined
Q-(2) Sol-(3)
Total cards = 52
Drawn Cards = 2
Present total cards = total cards – drawn cards = 52 – 2 = 50
Remaining cards = 13 – 2 = 11
Probability = 11/50
Q-(3) Sol-(3)
Total expenditure ( jan – jun) = 4200×6 = 25200
Total expenditure ( feb – june) = 25200 – 1200 = 24000
Total expenditure ( feb – jul) = 24000 + 1500 = 25500
Required answer=25500/6=4250
Q-(4) Sol-(4)
Downstream speed = 10+4 = 14
Upstream speed = 10 – 4 = 6
Now total time is 26 hours
If distance between A and B is d, then distance BC = d/2
d/14+d/12=26
d=168
Q-(5) Sol-(3)
Downstream speed = 10+4 = 14
Upstream speed = 10 – 4 = 6
Now total time is 26 hours
If distance between A and B is d, then distance BC = d/2
d/14+d/12=26
d=168
Q-(5) Sol-(3)
Area required = curved
surface area + Area of base = 594
Q-(6) Sol-(3)
845–625=?
?=220
Q-(7) Sol-(3)
18868–1760=?3
?3=17108
? 
26
Q-(8) Sol-(3)26
555–121=?×1.5
? 290
Q-(9) Sol-(1)290
7569+3844–1764=?×9
?=9649/9
?1072
Q-(10) Sol-(2)1072
12167–3136=?×7
?1290
1290
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