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Quantitative Aptitude Quiz For IBPS Clerk Mains| 17-01-2020

Durgesh Mahendras
Quantitative Aptitude Quiz For IBPS Clerk Mains| 17-01-2020



Dear All,


As you all know that IBPS Clerk Mains exams dates are approaching and it is high time for you to start your preparation for the exam. In order to make you prepared for the examination, Mahendras has started new quizzes of Maths, English & Reasoning section of the IBPS Clerk Mains, these quizzes will be very beneficial for the exam. You can practice these quizzes on daily basis.




Instruction: - Bar graph shows that five student from school X did work in different days. And line graph shows that five girls from same class dad the same work in different days.

IBPS-CLERK-MAINS-17-1-2020


IBPS-CLERK-MAINS-17-1-2020

Q.1:- Jayant started the work and work for 3 days then left Aditi and Sneha complete the remaining part of the work in how many days?

जयंत ने काम शुरू किया और 3 दिनों तक काम किया और छोड़ दिया फिर अदिति और स्नेहा ने बचा हुआ काम कितने दिनों में दिया?

(1) 18 days
(2) 10 days
(3) 15 days
(4) None of these/ इनमे से कोई नहीं
(5) 12 days


Q.2. If Amitosh works with twice the efficiency as he does it before, Akhilesh does 25% of his efficiency and Swinka does half of her efficiency as she does before. What is the difference of number of days taken by them when they work altogether from usual time to new one?

यदि अमितोष अपनी क्षमता से दोगुनी क्षमता से काम करता है अखिलेश अपनी क्षमता का 25% क्षमता से और स्विंका अपनी क्षमता का 50% से काम करते है तो उनके द्वारा लिए गए समय और पहले के समय का अंतर ज्ञात करें जब वो एक साथ काम करते है ?

(1) 1(63/767) days
(2) 1(77/767) days
(3) 1(75/767) days
(4) 1(73/767) days
(5) 1(70/767) days


Q.3:-Find the respective ratio of efficiencies of Sarvesh and Akhilesh together and efficiencies of Aditi and Sneha together?

सर्वेश और अखिलेश की क्षमताओं और अदिति और स्नेह की क्षमताओं का अनुपात क्या होगा?

(1) 7:5
(2) 5:7
(3) 4:5
(4) can’t be determined/ ज्ञात नहीं कर सकते
(5) none of these/ इनमे से कोई नहीं

Q.4:- If Amitosh and Priyanka work alternately started with Amitosh, find the number of days taken by them to complete the work?

यदि अमितोष और प्रियंका एकांतर दिनों में काम करती है जिसे अमितोष शुरू करता है तो काम कितने दिनों में समाप्त होगा ?

(1) 22(1/5) days
(2) 25(1/4) days
(3) 23(1/6) days
(4) 27(1/2) days
(5) None of these


Q.5.Jayant and Amitosh started the work and left after four days. Find the number of days taken by Sneha to complete the remaining part of the work?

जयंत और अमितोष काम को शुरू करते है और चार दिन बाद छोड़ देते है स्नेहा बचे हुए का को कितने दिनों में समाप्त कर देगी?

(1) 52/3
(2) 40/3
(3) 16(2/3)
(4) 26(2/3) days
(5) None of these/ इनमे से कोई नहीं


Instruction:- (06 – 10):- find the missing term in the following number series?

Q.6:-    6615   ,   (?)     ,   105   ,     21     ,      7

(1) 775
(2) 745
(3) 735
(4) 725

(5) None of these/ इनमे से कोई नहीं

Q.7:- 1399  ,    (?)    , 117     ,     23 ,        4

(1) 445
(2) 365
(3) 345
(4) 465
(5) None of these/ इनमे से कोई नहीं


Q.8:-      3     ,     12      ,     108         , 1728        ,    (?)

(1) 46800
(2) 45600
(3) 32400
(4) 43000
(5) 43200


Q.9:-     (?)     ,      4      ,      6       ,       15   ,      52.5

(1) 2
(2) 1
(3) 8
(4) 16
(5) None of these/ इनमे से कोई नहीं


Q.10:-    9261     ,       10648   ,    12167    ,       (?)     ,      15625

(1) 13514
(2)  13614
(3) 13824
(4) 13714
(5) 13734









Answer:-

1. Sol:- (5)

One day work of Jayant = 1/30
3 days work of Jayant = 3/30  = 1/10
Remaining work = 9/10
9/ 10th part of the work done by Aditi in (9 x 20)/ 10 = 18 days.
9/ 10th part of the work done by Sneha in ((9 x 40)/ 10 = 36 days.
Together they can complete the work = (18 x 36)/54 = 12 days


2. Sol:- (4)


Number of days taken by them when they work with their original efficiency
Amitosh ---- 20 days                       eff  = 6
Akhilesh ---- 40 days    lcm = 120       eff  = 3
Swinka ------ 30 days                       eff. = 4
Number of days taken by all of them to work altogether = 120/ 13
ATQ
Amitosh ------ 10 days                              eff. = 48
Akhilesh ------- 160 day        LCM = 480   eff. = 3
Swinka -------    60 day                              eff = 8

Required number of days = 480/ 59
Required difference = 840/ 767 days
= 1(73/767) days


3. Sol:- (2)

One day work of Sarvesh (eff.) = 1/35
One day work of Akhilesh (eff.) = 1/40
One day work of Sneha = 1/40
One day work of Aditi = 1/20
Required ratio = IBPS-CLERK-MAINS-17-1-2020
=  5 : 7


4.Sol:- (2)

IBPS-CLERK-MAINS-17-1-2020 


5. Sol:- (4)


Jayant’s one day work = 1/30
Jayant’s four day work = 4/30
Amitosh one day work = 1/20
Amitosh four day work = 4/20
When they work together = (4/30 + 4/20)
= 1/3 work completed by Amitosh and Jayant
Remaining 2/3 work done by Sneha = 26(2/3) days


6.Sol:- (4)

Logic = IBPS-CLERK-MAINS-17-1-2020


7. Sol: - (4)

Logic: - IBPS-CLERK-MAINS-17-1-2020………

8.Sol:- (5)

Logic:- IBPS-CLERK-MAINS-17-1-2020

9. Sol:- (3)

Logic:- IBPS-CLERK-MAINS-17-1-2020 

10. Sol:- (3)

Logic:- IBPS-CLERK-MAINS-17-1-2020 

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