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यदि 2a + 3b = 17 और 2a+2 – 3b+1 = 5, तो a + b का मान ज्ञात कीजिये |
- 1
- 2
- 4
- 5
हल कीजिये:
C का मान ज्ञात कीजिये, यदि समीकरण x3 + x2 – 5x + C, (x - 2) से विभाजित हैं ।
- 2
- -2
- 3
- -4
हल कीजिये:
- -1
- 1
- 0
- x + y
20 आदमी एक काम को 18 दिन में कर सकते है उहोने 3 दिन मिलकर काम किया उसके बाद 5 आदमी उनके साथ शामिल हो गए. काम कितने दिनों में पूरा हो जायेगा?
(A) 13
(B) 12
(C) 14
(D) 15
Q6.) The ratio of the ages of A and B at present is 3 : 1. Four year earlier the ratio was 4 : 1. The present age of A is :
वर्तमान में A और B की आयु का अनुपात 3 : 1 है चार वर्ष पूर्व अनुपात 4 : 1 था ! A की वर्तमान आयु कितनी है ?
(A) 48 years
(B) 40 years
(C) 32 years
(D) 36 years
Q7.) The term that should be added to (4x2 + 8x) so that resulting expression be a perfect square is:
(4x2 + 8x) में कौन सी संख्या जोड़ी जाये की परिणामी पद संहित पूर्ण वर्ग बन जाये?
(A) 2
(B) 4
(C) 1
(D) 2x
Q8.) A certain amount of money earns Rs. 540 as simple interest in 3 years. If it earns a compound interest of Rs. 376.20 at the same rate of interest in 2 years, find the amount.
किसी धनराशि पर साधारण ब्याज के रूप में 3 वर्ष में रु. 540 मिलते है यदि 2 वर्ष में उतनी ही ब्याज दर पर रु. 376.20 का चक्रव्रिधि ब्याज मिले तो राशि ज्ञात कीजिये?
(A) 2000
(B) 2100
(C) 1600
(D) 1800
Q9.) The average of some natural numbers is 15. If 30 is added to first number and 5 is subtracted from the last number, the average become 17.5. then the numbers of natural numbers is :
कुछ प्राकृत संख्याओ का औसत 15 है यदि पहली संख्या में 30 जोड़ा जाये और अंतिम संख्या में 5 घटा दिया जाये तो औसत 17.5 रहता है प्राकृत संख्याओ की संख्या कितनी है?
(A) 10
(B) 20
(C) 30
(D) 15
Q10.) The LCM of two numbers is 12 times their HCF. The sum of HCF and LCM is 403. If one number is 93, then find the other number?
दो संख्याओ का ल.स.प. 12 गुना है म.स.प का, उनके म.स.प. और ल.स.प. का योग 403 है यदि एक संख्या 93 है तो दूसरी संख्या ज्ञात किजिये?
(A) 124
(B) 248
(C) 372
(D) 403
SOLUTION :
By hit and trial method a =3 and b = 2
Check it by putting values in equation
23 + 32 = 8 + 9 = 17
25 – 33 = 32 – 27 = 5
Q2.) (A)
Q3.) (B)
x – 2 = 0
x = 2
23 + 22 – 5×2 + C = 0
C = -2
Q4.) (B)
Q5.) (B)
20 men can do a piece of work in 18 days.
Then total work = 20 x 18 = 360
If they worked for 3 days then, the 3 days work is = 20 x 3 = 60.
Remaining work = 360 – 60 = 300
If 5 men joined the work then the remaining work will be finished in
Q6.) (D)
Let the ratio be x.
A = 3x B = x.
Four year ago,
x = 12
Then the present age of A is 36 years.
Q7.) (B)
(4x2 + 8x + 4) = (2x +2)2
Required ans is 4.
Q8.) (A)
If 3 years S.I is 540 then one year S.I will be 180.
If two year CI is 376.20 then we can say that
Then rate of interest is 9 %.
So
Q9.) (A)
Let the numbers be x.
According to question,
Q10.) (A)
Let HCF = x. then LCM = 12x.
Given that,
HCF = 31 and LCM = 12 x 31
Other number =
